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juin [17]
3 years ago
12

How do rising temperature affect the process of convection

Physics
2 answers:
Papessa [141]3 years ago
4 0

<span>Convection is a process of heat transfer between a surface and a moving fluid. It occurs when the air has a lower temperature than the body, and the body transfers heat through contact with the cold air around it. Air heating causes it to rise. The increase in temperature affects the convection process, since as the warm air rises, the cold air takes its place, thus completing its convection cycle. Example: Wind</span>
Lady bird [3.3K]3 years ago
3 0
Convection is the transfer of heat from a warmer region to a cooler one by moving warm liquid or gas from the heated area to the unheated area. In a boiling pot of water, hot water in the bottom of the pot rises to the surface, leading to bubbles of heated water and sometimes steam visible on the surface. In meteorology, convection is often associated with rising air and clouds, and at times, thunderstorms. Air that is rising cools as it reaches lower pressures, and may reach the point where water vapor in the air condenses and forms clouds.
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A student makes the following statement
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The current is not used up. The electrons flow through the entire circuit and this travel is the current. They flow until they are not charged anymore. That is also why the circuit must be closed or else electrons would escape not just light it up for a second then go out.

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A block is released to slide down a frictionless incline of 15∘ and then it encounters a frictional surface with a coefficient o
Elodia [21]

The block's potential energy at the top of the incline (at a height h from the horizontal surface) is equal to its kinetic energy at the bottom of the incline, so that

mgh = 1/2 mv²

where v is its speed at the bottom of the incline. It follows that

v = √(2gh)

If the incline is 20.4 m long, that means the block has a starting height of

sin(15°) = h/(20.4 m)   ⇒   h = (20.4 m) sin(15°) ≈ 5.2799 m

and so the block attains a speed of

v = √(2gh) ≈ 10.1728 m/s

The block then slides to a rest over a distance d. Kinetic friction exerts a magnitude F over this distance and performs an amount of work equal to Fd. By the work-energy theorem, this quantity is equal to the block's change in kinetic energy, so that

Fd = 0 - 1/2 mv²   ⇒   d = (-1293.58 J)/F

By Newton's second law, the net vertical force on the block as it slides is

∑ F [vertical] = n - mg = 0

where n is the magnitude of the normal force, so that

n = mg = (25 kg) g = 245 N

and thus the magnitude of friction is

F = -0.16 (245 N) = -39.2 N

(negative since it opposes the block's motion)

Then the block slides a distance of

d = (-1293.58 J) / (-39.2 N) ≈ 32.9994 m ≈ 33 m

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2 years ago
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