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juin [17]
3 years ago
12

How do rising temperature affect the process of convection

Physics
2 answers:
Papessa [141]3 years ago
4 0

<span>Convection is a process of heat transfer between a surface and a moving fluid. It occurs when the air has a lower temperature than the body, and the body transfers heat through contact with the cold air around it. Air heating causes it to rise. The increase in temperature affects the convection process, since as the warm air rises, the cold air takes its place, thus completing its convection cycle. Example: Wind</span>
Lady bird [3.3K]3 years ago
3 0
Convection is the transfer of heat from a warmer region to a cooler one by moving warm liquid or gas from the heated area to the unheated area. In a boiling pot of water, hot water in the bottom of the pot rises to the surface, leading to bubbles of heated water and sometimes steam visible on the surface. In meteorology, convection is often associated with rising air and clouds, and at times, thunderstorms. Air that is rising cools as it reaches lower pressures, and may reach the point where water vapor in the air condenses and forms clouds.
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Two cars collide and come to a complete stop. where did all of their energy go?
MA_775_DIABLO [31]
Most of the energy will be absorbed by the materials that make up the cars, causing them to deform. The energy will also be converted into sound energy, causing a loud bang upon collision. Also, some energy will be converted to thermal energy, which will cause the cars to heat up slightly.
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3 years ago
Ow much charge flows from a 12.0 v battery when it is connected across a completely discharged 18.0 μf capacitor
Trava [24]
The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or  18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).
5 0
2 years ago
Calculate the work done if a boy lifts a bag of cement 500N to the floor of a lorry 2.5m above the ground
eduard

Answer:

W = 1250 J = 1.25 KJ

Explanation:

The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:

W = P.E\\W = mgh

where,

W = Work done = ?

mg = W = weight of cement = 500 N

h = height covered = 2.5 m

Therefore,

W = (500\ N)(2.5\ m)

<u>W = 1250 J = 1.25 KJ</u>

4 0
2 years ago
Moon problem please help!
Mariulka [41]

Answer:

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4 0
3 years ago
Read 2 more answers
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
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