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The correct answer is B the total velocity is equal at both landing and launch because before your about launch you have 0 velocity then when you have landed you also have 0 velocity. Hope This Helps
Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by
.
<h3>What are equilibrium and resultant force?</h3>
The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.
<h3>Briefing:</h3>
3N and 4N are the two forces pulling on a body.
The forces work along the North and the East, which are perpendicular to one another.
The resultant of the forces, which is provided by the equilibrant force,
R = √(3)²+(4)²
R = 5N
From East, the equilibrant's angle is given by

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Answer:
432 units
Explanation:
Let the charges be q and Q separated by a distance r. The electrostatic force , F = kqQ/r² = 72 units. If q = 2q and Q = 3Q, then the new electrostatic force is
F = k × 2q × 3Q/r² = 6kqQ/r² = 6 × 72 = 432 units
Answer:
9.43 m/s
Explanation:
First of all, we calculate the final kinetic energy of the car.
According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

where
W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)
is the final kinetic energy
is the initial kinetic energy
Solving,

Now we can find the final speed of the car by using the formula for kinetic energy

where
m = 661 kg is the mass of the car
v is its final speed
Solving for v, we find
