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frosja888 [35]
2 years ago
15

PLS HELP!!! WILL GIVE BRAINLIEST

Physics
2 answers:
grandymaker [24]2 years ago
8 0

Answer:

did you ever get the answer

kumpel [21]2 years ago
8 0

Answer:

The correct answer is c

Explanation:

it was on a test and i got it right. :)

Hope this helps and have a good day ;)

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An elevator is rising up a vertical shaft in a skyscraper. Between the 12th and 20th floors, it travels at a constant speed. Dur
zaharov [31]
3. The upward force is greater
.................,
8 0
3 years ago
Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt
Ivenika [448]

Answer:

<em>The drop voltage is 0.3 V</em>

Explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

\displaystyle i=\frac{\varepsilon }{R_e+R_i}

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

\displaystyle i=\frac{24 }{158+2}

\displaystyle i=\frac{24 }{160}

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

V_i = i.R_i

V_i = 0.15*2

\boxed{V_i = 0.3\ V}

The drop voltage is 0.3 V

3 0
3 years ago
Will give brainliest! 50 points!!!
tatiyna

Answer:

C

Im not totally sure but that's what my science teacher taught me sorry if is wrong

6 0
3 years ago
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
Angelina_Jolie [31]

Answer:

Explanation:

<h3>that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.</h3>
3 0
2 years ago
A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha
goblinko [34]

Answer: 15.66 °

Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:

F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

8 0
3 years ago
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