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tiny-mole [99]
3 years ago
10

The cretaceous-paleogene was a mass extinction event in which nearly every single large, land-dwelling dinosaur went extinct. WH

ich of the following did not result from this extinction event?
.Diverse species of animals began to evolve
.Meteorites struck the region that Mexico now occupies
.Clouds of dust and gas billowed into Earths atmosphere
.Ecological niches were empty but with the potential to be filled
Physics
2 answers:
7nadin3 [17]3 years ago
8 0

The correct answer is Meteorites struck the region that Mexico now occupies.

The Cretaceous–Paleogene was a sudden mass extinction that took place approximately 66 million years ago. This event killed almost three quarter of the plants and animals species on earth. Almost all the animals were killed in this event weighing more than 25 kilograms. It was caused because of the impact of the comet and asteroid which destructed the global environment. Iridium was found in large amount in earth's crust, which is not a component of earth's crust. It is found in asteroids in huge amount.

Hence, when meteorites were not involved in the process then how come the meteorites get stuck in the region that now occupied as Mexico.


vlabodo [156]3 years ago
6 0

.Meteorites struck the region that Mexico now occupies

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In the space below, write one sentence describing how particles move in a longitudinal wave. Then, write two more sentences desc
kupik [55]

Answer:

First statement: The particles which are displaced is parallel to the direction of energy transport or to the direction the wave travels.

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4 years ago
Car A is accelerating in the direction of its motion at the rate of 3 ft /sec2. Car B is rounding a curve of 440-ft radius at a
Katena32 [7]

Answer:

Incomplete question

Check attachment for the diagram of the problem.

Explanation:

The acceleration of the car A is given as

a=3ft/s²

Car B is rounding a curve of radius

r=440ft

Car B is moving at constant speed of Vb=30mi/hr.

Car A reach a speed of 45mi/hr

Note, 1 mile = 5280ft

And 1 hour= 3600s

Then

Va=45mi/hr=45×5280/3600

Va=66ft/s

Also,

Vb=30mi/hour=30×5280/3600

Vb=44ft/s

Now,

a. Let write the relative velocity of car B, relative to car A

Vb = Va + Vb/a

Then,

Using triangle rule, because vectors cannot be added automatically

Vb/a²= Vb²+Va²-2Va•VbCosθ

From the given graphical question the angle between Va and Vb is 60°.

Vb/a²=44²+66² - 2•44•66Cos60

Vb/a²=1936+ 4356 - 5808Cos60

Vb/a² = 3388

Vb/a = √3388

Vb/a = 58.21 ft/s

The direction is given as

Using Sine Rule

a/SinA = b/SinB = c/SinC

i.e.

Va/SinA = Vb/SinB = (Vb/a)/SinC

66/SinA = 44/SinB = 58.21/Sin60

Then, to get B

44/SinB = 58.21/Sin60

44Sin60/58.21  = SinB

0.6546 = SinB

B=arcsin(0.6546)

B=40.89°

b. The acceleration of Car B due to Car A.

Let write the relative acceleration  of car B, relative to car A.

Let Aa be acceleration of car A

Ab be the acceleration of car B.

Ab = Aa + Ab/a

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Aa=3ft/s²

Then to get the acceleration of car B, using the tangential acceleration formular

a = v²/r

Ab = Vb²/r

Ab = 44²/440

Ab = 4.4ft/s²

Using cosine rule again as above

Ab/a²= Aa²+Ab² - 2•Aa•Ab•Cosθ

Ab/a²= 3²+4.4²- 2•3•4.4•Cos30

Ab/a²= 9+19.36 - 22.863

Ab/a² = 5.497

Ab/a = √5.497

Ab/a = 2.34ft/s²

To get the direction using Sine rule again, as done above

Using Sine Rule

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Aa/SinA = Ab/SinB = (Ab/a)/SinC

3/SinA = 4.4/SinB = 2.34/Sin30

Then, to get B

4.4/SinB = 2.34/Sin30

4.4Sin30/2.34 = SinB

0.9402 = SinB

B=arcsin(0.9402)

B=70.1°

Since B is obtuse, the other solution for Sine is given as

B= nπ - θ.   , when n=1

B=180-70.1

B=109.92°

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