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tiny-mole [99]
3 years ago
10

The cretaceous-paleogene was a mass extinction event in which nearly every single large, land-dwelling dinosaur went extinct. WH

ich of the following did not result from this extinction event?
.Diverse species of animals began to evolve
.Meteorites struck the region that Mexico now occupies
.Clouds of dust and gas billowed into Earths atmosphere
.Ecological niches were empty but with the potential to be filled
Physics
2 answers:
7nadin3 [17]3 years ago
8 0

The correct answer is Meteorites struck the region that Mexico now occupies.

The Cretaceous–Paleogene was a sudden mass extinction that took place approximately 66 million years ago. This event killed almost three quarter of the plants and animals species on earth. Almost all the animals were killed in this event weighing more than 25 kilograms. It was caused because of the impact of the comet and asteroid which destructed the global environment. Iridium was found in large amount in earth's crust, which is not a component of earth's crust. It is found in asteroids in huge amount.

Hence, when meteorites were not involved in the process then how come the meteorites get stuck in the region that now occupied as Mexico.


vlabodo [156]3 years ago
6 0

.Meteorites struck the region that Mexico now occupies

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Which of the following would be the best insulator? air aluminum copper silver
77julia77 [94]

Answer:

aluminum will be the best insulator...coz it have a high resistance

4 0
3 years ago
A 1350 kg uniform boom is supported by a cable. The length of the boom is l. The cable is connected 1/4 the
olchik [2.2K]

Answer:

Tension= 21,900N

Components of Normal force

Fnx= 17900N

Fny= 22700N

FN= 28900N

Explanation:

Tension in the cable is calculated by:

Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium

FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)

Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)

Ftorque= 2/3FBcostheta+ 4/3FWcostheta

Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°

Ftorque= 21900N

b) components of Normal force

Efx=FNx-FTcos(90-theta)=0 static equilibrium

Fnx=21900cos(90-55)=17900N

Fy=FNy+ FTsin(90-theta)-FB-FW=0

FNy= -FTsin(90-55)+FB+FW

FNy= -21900sin(35)+(1350+2250)×9.81=22700N

The Normal force

FN=sqrt(17900^2+22700^2)

FN= 28.900N

4 0
3 years ago
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0
3 years ago
Please answer fast in hindi ​
Ipatiy [6.2K]

Answer:

1. Dheere Dheere (slowly slowly)

2. Har (every)

3. Kal (tomorrow)

4. Mat (don't)

5. Andar (inside)

sorry I wasn't able to write in hindi

8 0
2 years ago
Aiden takes 0.10s to throw a baseball, which leaves his hand with a velocity of 49m/s. The balls acceleration is
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Since the ball was not moving before it let Aiden's hand, the formula used to calculate the acceleration is
a =  \frac{v}{t}
, where a is acceleration, v is velocity and t is the time. We put them in the formula and get
a =  \frac{49}{0.1}  \\ a =  \frac{490}{1}  \\ a = 490
The acceleration is 490 m/s^2
7 0
3 years ago
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