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Darya [45]
3 years ago
14

a stone is thrown vertically upwards with an initial velocity of 20 metre per second find the maximum height it reaches and the

time taken by to reach the height( g =10m/s)​
Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

y = 20 [m]

Explanation:

To solve this type of problem we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}-2*g*y

where:

Vf = final velocity = 0

Vo = initial velocity = 20 [m/s]

g = gravity acceleration = 10 [m/s²]

y = elevation [m]

Now the key to solving this problem is to know that when the stone reaches the maximum height its speed is zero. Therefore the final velocity term is zero.

0 = (20)^{2}-2*10*y\\20*y=400\\y=20 [m]

Another important fact is that the sign of gravitational acceleration was taken as negative, since it acts in the opposite direction to the movement of the stone.

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In which situation is the maximum possible work done?
ExtremeBDS [4]

Answer:

Answer is A.

Explanation:

Remember the equation for work:

W = F d cos θ

Math explanation: When θ = 0, cos θ = 1, so Fd is a maximum. For any other value of θ up to 90 degrees, cos θ < 1 so Fd will be smaller. For θ = 180, you're pushing away from the direction of displacement so you're actually doing negative work.

Intuitive explanation: you have the most success pushing an object when you apply the force directly against it compared to if the force was directed at an angle.

3 0
3 years ago
On a spacecraft, two engines are turned on for 789 s at a moment when the velocity of the craft has x and y components of v0x =
ddd [48]

Answer:

Explanation:

Given

time for which spacecraft turned on is 789 s

v_{0x}=5410 m/s

v_{0y}=8100 m/s

x=2.78\times 10^6 m

y=4.73\times 10^6 m

we know s=ut+\frac{at^2}{2}

2.78\times 10^6=5410\times 789+\frac{a_x(789)^2}{2}

2.78=4.268+a_x\times 0.622

a_x=-2.392 m/s^2

For y component

s=ut+\frac{at^2}{2}

4.73\times 10^6=8100\times 789+\frac{a_y(789)^2}{2}

4.73=6.39+a_y\times 0.622

a_y=-2.66 m/s^2

4 0
4 years ago
D
Ber [7]

Answer:

D

Explanation:

I think you got it right

3 0
3 years ago
Read 2 more answers
A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wr
Sunny_sXe [5.5K]

Answer:

Explanation:

Torque created by force 3.34N

= 3.34 x 1.39 = 4.64 N.m

This torque is acting in clockwise direction .

Torque created by force 8.52 N

8.52 x .48

= 4.09 N.m

The force of 8.52 N is acting downward . It may turn the cylinder in clockwise or anticlockwise direction . So we shall consider both the possibilities.

If it rotates the cylinder in clockwise direction

Total torque = 4.64 + 4.09

= 8.73 Nm

If it rotates the cylinder in anticlockwise direction

Total torque = 4.64 - 4.09

= .55 Nm

Net torque will be in clockwise direction.

5 0
3 years ago
In uniform circular motion, which of the following are constant:Check all that apply.Check all that apply.the speed is constantt
AlladinOne [14]

Answer:

The speed, magnitude of the velocity, magnitude of the angular velocity, magnitude of the centripetal acceleration, magnitude of the net force and direction of the angular velocity are constant.

Explanation:

In uniform circular motion we have a centripetal acceleration of constant magnitude but changing direction (since it points to the center of the circle from the object). The same goes for the net (centripetal) force since F=ma. This makes the magnitude of the velocity (speed) constant but its direction changes, although keeping spinning in the same direction, which makes its angular velocity constant in both magnitude and direction.

3 0
4 years ago
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