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Darya [45]
3 years ago
14

a stone is thrown vertically upwards with an initial velocity of 20 metre per second find the maximum height it reaches and the

time taken by to reach the height( g =10m/s)​
Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

y = 20 [m]

Explanation:

To solve this type of problem we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}-2*g*y

where:

Vf = final velocity = 0

Vo = initial velocity = 20 [m/s]

g = gravity acceleration = 10 [m/s²]

y = elevation [m]

Now the key to solving this problem is to know that when the stone reaches the maximum height its speed is zero. Therefore the final velocity term is zero.

0 = (20)^{2}-2*10*y\\20*y=400\\y=20 [m]

Another important fact is that the sign of gravitational acceleration was taken as negative, since it acts in the opposite direction to the movement of the stone.

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70 x v₁ + 0.15 x v₂=5.25                   --------1

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