a stone is thrown vertically upwards with an initial velocity of 20 metre per second find the maximum height it reaches and the
1 answer:
Answer:
y = 20 [m]
Explanation:
To solve this type of problem we must use the following equation of kinematics.
where:
Vf = final velocity = 0
Vo = initial velocity = 20 [m/s]
g = gravity acceleration = 10 [m/s²]
y = elevation [m]
Now the key to solving this problem is to know that when the stone reaches the maximum height its speed is zero. Therefore the final velocity term is zero.
Another important fact is that the sign of gravitational acceleration was taken as negative, since it acts in the opposite direction to the movement of the stone.
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The period of the orbit would increase as well
Explanation:
We can answer this question by applying Kepler's third law, which states that:
"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"
Mathematically,
Where
T is the orbital period
a is the semi-major axis of the orbit
In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, : but as we saw from the previous equation, the orbital period of the Earth is proportional to
, therefore as
increases, T increases as well.
Therefore, the period of the orbit would increase.
Learn more about Kepler's third law:
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