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3 years ago

Using r.i.v.p. How do I calculate circuits wit 12 volts

1 answer:

4 0

You don't calculate a circuit. You calculate the voltage, current, capacitance,
resistance, inductance, impedance, phase, power factor, frequency response,
or reflection coefficient of the circuit, and other stuff like that there.

Tell us what you need to find, and what information you have, and we'll
show you how to use what you have to find what you need to find.

You might be interested in

How much (in newtons) does a 10.0Kg bag of grass seed weigh

dimulka [17.4K]

Weight is equal to the mass of the object times the acceleration due to gravity (which is 9.8 $m/s^{2}$ on earth)

So W=mg
W=10.0 × 9.8 = 98

So the weight is 98N.

3 0

3 years ago

In one experiment, the teacher determined that the force on the wire was 2.14 mN

blsea [12.9K]

Answer:

in ine experiment the teacher determined

3 0

3 years ago

if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?

Scrat [10]

Answer:

It requires 1.9 seconds to reach maximum height.

Explanation:

As per given question,

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

$\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}$

Maximum height = S

Time taken is "t"

Calculating time taken to reach maximum height:

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

$0=19+10 \times t$

$-19=10 \times t$

$\frac{-19}{10}=t$

t = 1.9 seconds.

The time taken to reach maximum height is 1.9 seconds.

Calculating maximum height:

$\text { Consider the equation } V^{2}-U^{2}=2 a S$

Solving the equation we will get the value of S

$0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }$

-361 = -20S

Negative sign cancel both the sides.

$\mathrm{S}=\frac{361}{20}$

S = 18.05 m

Maximum height is 18.05 m .

3 0

3 years ago

If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t

STatiana [176]

Answer:

The velocity is $4.6 m/s^2$

Explanation:

Given:

Force = 500N

Distance s= 0

To find :

Its velocity at s = 0.5 m

Solution:

$\sum F_{x}=m a$

$F\left(\frac{4}{5}\right)-F_{S}=13 a$

$500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a$

$400-(500 s)=13 a$

$a = \frac{400 -(500s)}{13}$

$a = (30.77 -38.46s) m/s^2$

Using the relation,

$a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}$

$a=v \frac{d v}{d s}$

$v d v=a d s$

Now integrating on both sides

$\int_{0}^{v} v d v=\int_{0}^{0.5} a d s$

$\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s$

$\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}$

$\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]$

$\left[\frac{v^{2}}{2}\right]=[15.385-4.807]$

$\left[\frac{v^{2}}{2}\right]=10.578$

$v^{2}=10.578 \times 2$

$v^{2}=21.15$

$v = \sqrt{21.15}$

$v = 4.6 m/s^2$

8 0

3 years ago

Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of

lilavasa [31]

I don't know if you need to complete this question or do it otherwise, however, I managed to find on the Internet on several places this completion of your sentence:
Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of q = 2 x 10⁶ W/m³.
I'm not sure whether that is the answer you were looking for, but that's what I found.

6 0

3 years ago