The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is 
Explanation :
the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)
Apply section formula to find coordinates of point Q
Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)
Substitute all the values inside the formula
The coordinates of point Q is
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Answer:
creo que sería 54 por actitud de :72-1 1?? por eso sería esta cosa esxtactamente espero que te allá ayudado
<span> f(x)=4x^8+7x^7+1x^6+
</span>∴<span> f(-2)=4(-2)^8+7(-2)^7+1(-2)^6+1
</span>∴ <span>f(-2)=(4x256) + (7x-128) + (1x64) +1
</span>∴ <span>f(-2)=1024 - 896 + 64 +1
</span>∴ <span>f(-2)= 193</span>
Divide both sides by 2
x^2 = 128/2
Simplify 128/2 to 64
x^2 = 64
Take the square root of both sides;
x = √64
Since 8 * 8 = 64, the square root of 64 is 8
<em>x = -8 and 8</em>
<u>Answer: B -8 and 8</u>
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
