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ludmilkaskok [199]

3 years ago

8

Please help me with this very troubling algebra question, Thank you.

1 answer:

VladimirAG [237]3 years ago

3 0

The answer would have to be 52/87. Since it says "given", as in a geometric sense (proof), you know that the overall would have to be 87. It also adds that the students would be in the 10th grade, thus bringing us to the conclusion that 52/87 is correct. Then, simply use a calculator and put in 52/87. You're final answer, rounded to the nearest hundredth, should be 0.60.

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How to find a volume of a triangular prism

arlik [135]

Answer:

Remember the formula for calculating volume is: Volume = Area by height. V = A X h.

For a triangle the area is calculated using the formula: Area = half of base by altitude. A = 0.5 X b X a.

So to calculate the volume of a triangular prism, the formula is: V = 0.5 X b X a X h.

Step-by-step explanation:

hope it helps <33!

6 0

3 years ago

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Solve the system:<br> y = 3x<br> -x + 2y=5<br><br> (_,_)

kakasveta [241]

Answer:

(5, 15)

Step-by-step explanation:

-x + 6x = 5

5x = 5

x = 5

y = 3 (5)

y = 15

You can substitute 6x for 2y because it says y = 3x. So 2y is gonna be 6x because you have to multiply it by 2 since it's 2y not just y.

8 0

3 years ago

Which story problem could be solved using the given equation? 1/5×2/3=m

Ksju [112]

its b. hope this helps i guess

5 0

4 years ago

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11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *

kompoz [17]

Answer:

$c=0.4\ J/g^{\circ} C$

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C$

So, the specific heat of the material is $0.4\ J/g^{\circ} C$ .

3 0

3 years ago

Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?

Mademuasel [1]

Answer:- a.The given expression is equivalent to $\frac{x^{10}y^{14}}{729}$

Given expression:- $[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}$

$=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}$

$=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}$

$=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}$

$=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}$

$=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}$

Thus a. is the right answer.

6 0

3 years ago

Read 2 more answers