Answer:
a and c
Step-by-step explanation:
Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28
Answer:
4 and 9
Step-by-step explanation:
let their ages be x and x - 5, then in 4 years their ages will be
x + 4 and x - 5 + 4 = x - 1 , and the product is 104, thus
(x + 4)(x - 1) = 104 ← expand factors on left using FOIL
x² + 3x - 4 = 104 ( subtract 104 from both sides )
x² + 3x - 108 = 0 ← in standard form
(x + 12)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 12 = 0 ⇒ x = - 12
x - 9 = 0 ⇒ x = 9
However, x > 0 ⇒ x = 9
Thus
Their present ages are 9 and 9 - 5 = 4
