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3 years ago

Of the following forms of carbon dioxide, which has the lowest entropy?

Chemistry

1 answer:

saw5 [17]3 years ago

4 0

Those atoms which have same atomic numbers but different atomic misses are lowest entropy.

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Which of the following can’t replace hydrogen of acid in the chemical reaction

Kaylis [27]

Answer:

Copper - Gold are below Hydrogen and lean to the least reactive end. All of the elements above Hydrogen in the reactivity series will displace Hydrogen atoms from an acid during a reaction.

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3 years ago

What is the difference between ores and fosssil fuels

Daniel [21]

An ore contains minerals (metals etc) that have economic value.
Fossil fuels are organic material, which means that they are made from dead organisms.

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3 years ago

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Wich value gives the number of particles in 1 mol of a substance

juin [17]

Answer: 6.022x10²³ (Avogadro's Number)

Explanation: The number of particles in 1 mole of a substance is determined by the Avogadro's Number.

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3 years ago

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Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s) E∘= −0.45 V

Ag+aq)+e−→Ag(s) E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻ reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592 = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0

3 years ago

Gallium oxide, Ga.Oy, forms when gallium is combined with oxygen. A 1.25 g of Ga is allowed to react with excess oxygen and 1.68

mrs_skeptik [129]

Answer : The chemical formula of a compound is, $Ga_2O_3$

Solution : Given,

Mass of gallium = 1.25 g

Mass of gallium oxide = 1.68 g

Mass of oxygen = Mass of gallium oxide - Mass of gallium

Mass of oxygen = 1.68 - 1.25 = 0.43 g

Molar mass of Ga = 69.72 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of Ga = $\frac{\text{ given mass of Ga}}{\text{ molar mass of Ga}}= \frac{1.25g}{69.72g/mole}=0.0179moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.43g}{16g/mole}=0.027moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ga = $\frac{0.0179}{0.0179}=1$

For O = $\frac{0.027}{0.0179}=1.5$

The ratio of Ga : O = 1 : 1.5

To make in whole number we multiple ratio by 2, we get:

The ratio of Ga : O = 2 : 3

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $Ga_2O_3$

The empirical formula weight = 2(69.72) + 3(16) = 187.44 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{187.44}{187.44}=1$

Molecular formula = $(Ga_2O_3)_n=(Ga_2O_3)_1=Ga_2O_3$

Therefore, the chemical of the compound is, $Ga_2O_3$

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3 years ago