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3 years ago

Pythagorean Theron can someone help me solve this

Mathematics

1 answer:

horsena [70]3 years ago

3 0

So you need to make out the lengths for the triangle. For the height, you can subtract the short length (100) from the longer length (1250) to get the height of the triangle. The base is the length at the very top, 75. So right now you have 150 for height and 75 for the base. Now use the formula to get 75 root 5.

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Factor completely x2 + 20x + 99

Bad White [126]

$x^2 + 20x + 99=x^2+9x+11x+99=x(x+9)+11(x+9)=(x+11)(x+9)$

6 0

3 years ago

Please answer hurry!!!!

lutik1710 [3]

The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
$x + y \geq 6\\
4 + -2 \geq 6\\
2 \geq 6 
$
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
$x + y \geq 6\\ 
4 + 2 \geq 6\\ 
6 \geq 6 \\\\
x \geq 4\\
4 \geq 4$
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

-------

Answer: C) (4, 2)

6 0

3 years ago

Can someone help me ?

Alex Ar [27]

All you need to do is divide 2.25 by 2!

The answer is 1.125!

I hope this helps! :)

5 0

3 years ago

Find -7a-6B (Picture provided)

sertanlavr [38]

Answer:

Option c

$-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -7A

$-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)$

Now we perform operation -6B

$-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)$

Now we add the resulting matrices

$\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

7 0

3 years ago

Please help this is very confusing.

Leni [432]

Rotation 45 and rotation 90

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3 years ago