Radius is MN
Cord is TR
Hope this helps
Only two questions came up
Answer:
x = 2 or 1/4
Step-by-step explanation:
-13/4 -x= 1/2x -1
Collect like terms
-13/4+1=1/2x+x
Using LCM
(-13+4)/4=(1+2x²)/2x
9/4=(1+2x²)/2x
Cross multiply
9(2x)=4(1+2x²)
18x=4+8x²
Turn into quadratic and solve
8x²-18x+4
Using formulae method
-b±(√b²-4ac)/2a
Where a=8, b= -18 and c=4
(-(-18)±(√(-18)²-4(8)(4))/2(8)
(18±(√324-128))/16
(18±√196)/16
(18±14)/16
(18+14)/16 or (18-14)/16
32/16 or 4/16
2 or 1/4
Answer: Assuming the plumber will round up the hours, the answer is 335.
Step-by-step explanation:
You can use this equasion to solve the problem: 75+52x=c
In this case, x would equal the number of hours he would work and c would represent the final cost.
Basically, you can just multiply the hourly cost by the hours he works and then add the service fee. Hope this helped!
Saving I don’t know but please let me know :)
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
