Answer:
Bc = √63 ft
Step-by-step explanation:
Here, we want to get the length of BC
As we can see, there is a right angled triangle ABC, with 12ft being the hypotenuse and 9 ft the other side
So we want to get the third leg which is BC
we can use the Pythagoras’ theorem here
And that states that the square of the hypotenuse equals the sum of the squares of the two other sides
let the missing length be x
12^2 = x^2 + 9^2
144 = x^2 + 81
x^2 = 144-81
x^2 = 63
x = √63 ft
Answer:
Step-by-step explanation:
First you add 4 on both sides
X^2=0
Then you take square on both sides
X=+- the square root of 4
Simplify that
X=plus or minus 2
The answer can be either -2 or +2 (which is just 2)
Answer:
Step-by-step explanation:
Hi there,
x(x + 19) = -34
I'm going to solve your equation step-by-step.<span><span>x<span>(<span>x + 19</span>) </span></span>= <span>−34
</span></span>Step 1: Simplify both sides of the equation.<span><span><span>x2 </span>+ <span>19x </span></span>= <span>−34
</span></span>Step 2: Subtract -34 from both sides.<span><span><span><span>x2 </span>+ <span>19x </span></span>− <span>(<span>−34</span>) </span></span>= <span><span>−34 </span>− <span>(<span>−34</span>)
</span></span></span><span><span><span><span>x2 </span>+ <span>19x </span></span>+ 34 </span>= 0
</span>Step 3: Factor left side of equation.<span><span><span>(<span>x + 2</span>) </span><span>(<span>x + 17</span>) </span></span>= 0
</span>Step 4: Set factors equal to 0.<span><span><span>x + 2 </span>= <span><span><span>0<span> or </span></span>x </span>+ 17 </span></span>= 0
</span><span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−17
</span></span>Answer:<span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−<span>17
Hope this helps! :)</span></span></span>
Answer:
b)
Step-by-step explanation:
b) set up equations so they are equal to each other,
this is when f(x)=g(x) so our approximation was close.
c)solving it graphically is nearly impossible because the solution can be any value around the intersection. only way to be sure is to solve it symbolically.
