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hram777 [196]
2 years ago
7

Tonya has 39 packages. Each package weighs 6 pounds. Choose the best estimate of the total weight of the packages.

Mathematics
1 answer:
Sidana [21]2 years ago
5 0

Step-by-step explanation:

If were estimating, 39 is pretty close to 40 and 40x6 is 240 pounds. if we are getting exact about it, then 234 pounds

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Please help me with these 2 questions. 50 points
Flura [38]

Answer:

if you are looking for the area this are the answers

Step-by-step explanation:

4: 125yd^{2}

how: .5 x 25 x 10 = 125

/////////////////////////////////////

5: 104m^{2}

how: .5 x 16 x 13 = 104

remember to put the ".5" when you are multiplying

I hope this help you

have a good night :)

7 0
3 years ago
Given that θ=<img src="https://tex.z-dn.net/?f=cos%5E%7B-1%7D%20%28%5Cfrac%7B3%7D%7B5%7D%20%29" id="TexFormula1" title="cos^{-1}
GalinKa [24]

What? Can you re-type this?

5 0
3 years ago
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
2 years ago
A local business has an area reserved behind the store for a parking lot that is 78 meters long by 19 meters wide. The stalls of
S_A_V [24]

The total area available for cars to park will be 858m².

<h3>How to calculate the area?</h3>

The area of the parking lot will be:

= 78 × 19

= 1482m²

The area of aisle will be:

= 8 × 78

= 624m²

The available area will be:

= 1482m² - 624m²

= 858m².

The compact parking spaces that will fit in the lot will be:

N × 12.5 = 858

N = 858/12.5

N = 68

The non compact parking spaces that will fit in the lot will be:

N × 16.5 = 858

N = 858/16.5

N = 52

Learn more about area on:

brainly.com/question/7438648

#SPJ1

5 0
1 year ago
HEY I NEE HELP WILL GIVE BRAINLIST
Crazy boy [7]

Answer:

I can help as welllll

Step-by-step explanation:

7 0
2 years ago
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