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Reil [10]
3 years ago
10

ABDC is an isosceles trapezoid. Given only the choices below, which properties would you use to prove ACD ≅ BDC by SSS?

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0

Answer: The legs are congruent.

The diagonals are congruent.


Step-by-step explanation:

Given: ABDC is an isosceles trapezoid.

And we know that in isosceles trapezoid.

The legs and the diagonals are congruent.  [property of isosceles trapezoid]

Thus, in \triangle{ACD} and \triangle{BDC}

\overline{CD}=\overline{CD}....[\text{reflexive property}]

\overline{AC}=\overline{BD}..........[\text{ legs are congruent in isosceles trapezoid}]

\overline{AD}=\overline{BC}..........[\text{ diagonals are congruent in isosceles trapezoid}]

\Rightarrow\triangle{ACD}=\triangle{BDC}........[\text{SSS congruence postulate}]


Alexeev081 [22]3 years ago
4 0
I think the correct answer would be the first option. To prove that ACD ≅ BDC by virtue of the SSS or side-side-side postulate, it should be that the answer is related with the sides of the trapezoid and the best option would be that the <span> legs are congruent.</span>
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