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2 answers:

7 0

D. I believe bc part of the equation is (y-y one) and y one is -3 and two negatives make a positive. And 11 squared it 121

Andru [333]3 years ago

4 0

Answer:

$\text{C. }x^2+(y+3)^2=11$

Step-by-step explanation:

The equation of a circle with radius $r$ and center $(h, k)$ is given by:

$(x-h)^2+(y-k)^2=r^2$ .

What we're given:

radius of $\sqrt{11}$
center at $(0,-3)$

Substituting given values, we get:

$(x-0)^2+(y-(-3))^2=\sqrt{11}^2,\\\boxed{\text{C. }x^2+(y+3)^2=11}$

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A line segment or ray that is perpendicular to the segment at its midpoint is called

Dimas [21]

Perpendicular bisector

3 0

3 years ago

Find the volume of the cylinder. Use 3.14 for Pi. Round your answer to the nearest hundredth.the height is 13 and the radius is

NikAS [45]

Answer:

The volume of the cylinder is 2002 square units.

Step-by-step explanation:

It is given that,

Height of the cylinder, h = 13 units

Radius of the cylinder, r = 7 units

We need to find the volume of the cylinder. The formula of the volume of cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7}\times 7^2 \times 13\\\\V=2002\ \text{unit}^2$

So, the volume of the cylinder is 2002 square units.

4 0

3 years ago

the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g

Svetlanka [38]

Y = e^tanx - 2

To find at which point it crosses x axis we state that y= 0

e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599

3 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$