Question

HELP ME PLEASE!!!!!! asap

Answer 1

Here is your answer

Using Pythagoras' theorem

we know the

Hypotenuse^2= base^2+perpendicular^2

So here,

${x}^{2}={9}^{2}+{3}^{2}$

${x}^{2}=81+9$

${x}^{2}=90$

$x=\sqrt{90}$

$x=3\sqrt{10}$

HOPE IT IS USEFUL

Answer 2

Answer:

x = 3$\sqrt{10}$

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to solve for the hypotenuse x, that is

x² = 9² + 3³ = 81 + 9 = 90

Take the square root of both sides

x = $\sqrt{90}$ = $\sqrt{9(10)}$ = 3$\sqrt{10}$ ← exact value