tenth place: 18.2
hundredth place: 18.19
one place: 18
tens place: 20
hundred place: 0
I didn't know which one you needed so I did a bunch
Answer:
No solutions
Step-by-step explanation:
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
The answer is either x>-7 or x<-7 I think it is the first one but I haven’t done these in a while so I forget when to switch the signs
So 8w=4c and 2c=3g. divide the first equation by 2 and you get 4w=2c. merge the two equation give you 4w=2c=3g, or 4w=3g. multiply 4 on both sides give you 16w=12g. So 16 widgets equal how 12 goof-ups?
