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Lyrx [107]
3 years ago
14

PLease help please please please please help help help me me em e

Mathematics
2 answers:
juin [17]3 years ago
4 0
1) Which of the following is an example of a dilation?
The correct answer is A) The hearts.

2) If triangle ABC is reflected across line m, the new coordinates will be located at A'(2, -4) B'(7,-7) C'(-2, -7).
The answer is False.

I hope this helps! I can't really see #3. Sorry. But I got #'s 1 & 2 though!
Minchanka [31]3 years ago
4 0
1.) In first question, option 1 is an example of dilation bcuz heart is enlarged. 2.) In second question, reflection should be A( 2,-4) , B(7,-9) and C(-2,-9) so false. 3.) Volume of sphere = 4/3 π r^3 = 4/3 π x ( 27/2)^3 = 10,305.99ft^3. Hence it is true.
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What does 6 - 6 + 3 =
Mice21 [21]

Answer:

3

Step-by-step explanation:

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3 years ago
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Peter buys a camper van costing £35000 + 20% VAT. He pays a 50% deposit and then arranges to pay the remaining balance in 20 equ
shutvik [7]

The amount paid each month is 1050.

35,000 plus 20% is 42,000 because 20% of 35,000 is 7,000.

Next, divide 42,000 by 20, and you would get 1050.

3 0
3 years ago
Find all the solutions for the equation:
Contact [7]

2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0

Divide both sides by x^2\,\mathrm dx to get

2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}

Substitute v(x)=\dfrac{y(x)}x, so that \dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}. Then

x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}

The remaining ODE is separable. Separating the variables gives

\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x

Integrate both sides. On the left, split up the integrand into partial fractions.

\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}

\implies v^2+2v+1=a(v^2+1)+(bv+c)v

\implies v^2+2v+1=(a+b)v^2+cv+a

\implies a=1,b=0,c=2

Then

\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v

On the right, we have

\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C

Solving for v(x) explicitly is unlikely to succeed, so we leave the solution in implicit form,

\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C

and finally solve in terms of y(x) by replacing v(x)=\dfrac{y(x)}x:

\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}

7 0
3 years ago
The diameter of a circle is 4 inches. What is the area ? Give the exact answer in the simplest form.
pychu [463]

Answer:

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alexandr402 [8]
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First you have to find out the measure of the two other angles in the triangle. Those two angles will be equivalent.

Because the sum of all three angles in a triangle is 180, you subtract 36 from it (180 - 36 = 144) then divide by 2 (144/2 = 72).

So, the two angles at the bottom of the triangle are each 72. Because those angles are supplementary to the angles at the top of the trapezoid, you subtract 72 from 180 (180 - 72 = 108).

108 + 108 = 216

The sum of all the angles in a trapezoid is 360, so subtract 216 from 360 (360 - 216 = 144) then divide by 2 (144/2 = 72)
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