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DedPeter [7]
3 years ago
7

Help please!

Physics
1 answer:
kipiarov [429]3 years ago
3 0
<h2>Answer: Diamond</h2>

Explanation:

This described situation is known as Refraction, a phenomenon in which the light bends or changes it direction when passing through a medium with a index of refraction different from the other medium.  

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2}) (1)  

Where:  

n_{1}=1 is the first medium index of refraction  (air)

n_{2} is the second medium index of refraction (the value we want to know)

\theta_{1}=27\° is the angle of the incident ray  

\theta_{2}=11\° is the angle of the refracted ray

Now, let's find n_{2} from (1):

n_{2}=n_{1}\frac{sin(\theta_{1}}{sin(\theta_{2}} (2)  

Substituting the known values:

n_{2}=(1)\frac{sin(27\°)}{sin(11\°)}}

Finally:

n_{2}=2.379\approx 2.4

If we compare this result with the given table, the index of refraction value that is close to this number is diamond's index of refraction.

Therefore, the correct option is A: the material is diamond.

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Step 1: Find the upward acceleration. 
d = 107 m 
a = ??? 
vi = 0 
t = 14.4 sec 
d = vi * t + 1/2 at^2 
107 = 1/2 a * 14.4^2 
a = 214 / (14.4)^2 
a = 1.03 m/s^2 
Step 2: Find the Volume of the balloon and from that the mass. 

V = 4/3 * pi * r^3 
r = 6.52 m 
V = 4/3 x pi x 6.52^3
V= 1,161 m^3.
Density of air = m/V 1.29 = m/ 1161 
M = 1.29 x 1161
m = 1498 kg 
Step 3: The force keeping this in equilibrium = F = m* g 
F = 1498 * 9.81 = 14692 N 
Step 4: Find the mass needed to cause the upward acceleration. 
14692 = (1498 - x) * (9.81 + 1.03) 
14692 = (1498 - x) *  10.84 Divide both sides by 10.84 
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7 0
3 years ago
The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d
Mademuasel [1]

Answer:

28.11m far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

  (1). \: \:\beta =10 log(\dfrac{I}{I_0})

The ratio of the intensities can be written as

$ \frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} } $

\dfrac{I}{I_0} = \dfrac{A_0}{A}.

And since

A = 4\pi r^2

and

A_0 = 4 \pi r_0^2,

\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2}  = \dfrac{r_0^2}{r^2}

meaning

\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.

Putting this into equation (1), we get:

\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

100dB=10 log(\dfrac{r_02}{(5m)^2})

10= log(\dfrac{r_0^2}{25})

by taking both sides to the exponent:  

10^{10}= \dfrac{r_0^2}{25}

r^2 = 25 *10^{10}\\r = 5 *10^5

Now equation (2) becomes

\beta = 10log(\dfrac{25*10^{10}}{r^2})

when the intensity level is 85 dB we have

85 = 10log(\dfrac{25*10^{10}}{r^2})

8.5 = log(\dfrac{25*10^{10}}{r^2})

take both sides to exponents and we get:

10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}

10^{8.5} =\dfrac{25*10^{10}}{r^2}

r^2 = \dfrac{25*10^{10}}{10^{8.5}}

\boxed{r = 28.11m}

Thus, 28.11m far from the speaker the intensity drops to 85 dB.

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Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati
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Answer:

The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

         Let C denote the circumference

      So  

               C = 2 \pi r

      =>     r = \frac{C}{2 \pi}

               r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142}  = 6.365*10^6 m

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

       The final length would be

                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

  let L_{final} denote the final length

   So

        L_{final} =40000*10^{6} *[1+ 11*10^{-6}]

                  = 40000440 \ m

 Now the Height is mathematically represented as

         Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}

                       = \frac{(40000440-40000*10^3)}{2*3.142}

                       = 70.02m

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