Question:
A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero
Answer:
24 m/s
Explanation:
Given:
x=(24t - 2.0t³)m
First find velocity function v(t):
v(t) = ẋ(t) = 24 - 2*3t²
v(t) = ẋ(t) = 24 - 6t²
Find the acceleration function a(t):
a(t) = Ẍ(t) = V(t) = -6*2t
a(t) = Ẍ(t) = V(t) = -12t
At acceleration = 0, take time as T in velocity function.
0 =v(T) = 24 - 6T²
Solve for T
Substitute -2 for t in acceleration function:
a(t) = a(T) = a(-2) = -12(-2) = 24 m/s
Acceleration = 24m/s
Answer:
Explanation:
This problem is related to vertical motion, and the equation that models it is:
(1)
Where:
is the rock's final height
is the rock's initial height
is the rock's initial velocity
is the angle at which the rock was thrown (directly upwards)
is the time
is the acceleration due gravity in Planet X
Isolating and taking into account 
:
(2)
(3)
(4) This is the acceleration due gravity in Planet X
Answer:
<h2>
The magnitude of force F is 18N</h2>
Explanation:
The magnitude of the force in the set up can be solved for using the principle of moment. According to the principle, the sum of clockwise moment is equal to the sum of anticlockwise moments.
Moment = Force * perpendicular distance
Clockwise moments;
The force that acts clockwise is the unknown Force F and 4N force. If the beam rests on a pivot 60 cm from end X and a Force F acts on the beam 80 cm from end X, the perpendicular distance of the force F from the pivot is 80-60 = 20cm and the perpendicular distance of the 4N force from the pivot is 60-50 = 10cm
Moment of force F about the pivot = F * 20
Moment of 4N force about the pivot = 4*10 = 40Nm
Sum of clockwise moment = 40+20F...(1)
Anticlockwise moment;
The 8N will act anticlockwisely about the pivot.
The distance between the 8N force and the pivot is 60-10 = 50cm
Moment of the 8N force = 8*50
=400Nm...(1)
Equating 1 and 2 we have;
40+20F = 400
20F = 400-40
20F = 360
F = 18N
The magnitude of force F is 18N
Hi, here is the first part of the answer..do you know what type of graph it's wanting?? (line graph, bar graph, ect.)
Answer:
686.11 N
1.7733 gallons
Explanation:
= Efficiency = 30%
V = Volume of gasoline
E = Energy content of gasoline = 
F = Force
s = Displacement = 108000 m
v = Velocity
Work done is given by
The force required to keep the car moving at a constant speed is 686.11 N
Here the force is directly proportional to speed
The gallons that will be used is 1.7733 gallons
