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2 years ago

Which point on the graph below is included in the solution to the following system of equations?

Mathematics

1 answer:

monitta2 years ago

5 0

Answer:

D(-7,-2)

Step-by-step explanation:

A(-4,3) B(5,-1) C(-2,-6) D(-7,-2)

A: 5×(-4) + 6×3 = -2 ≥ -30 ..... No

B: 2/3×5 + 1 =4.33 ≥ -1 ....No

C: -6 ≤ 2/3×-2 +1 ....No

D: 2/3×(-7)+1 = 2.333 ≤ -2

5×(-7) + 6×(-2) = -47 ≤ -30 ......Yes

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एउटा आयताकार चाउरको परिमिति 1004 m भए सो चउरको

frez [133]

Answer:

502m

Step-by-step explanation:

let x and y represent the length and breadth of rectangular meadow respectively.

Given,

Perimeter of the meadow =1004m

or,2(l+b)=1004m

or2(x+y)=1004m

orx+y=1004m/2

or,x+y=502m

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What is the value of -25 + 50 - 20 + (-12) Absolute Value

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-7 is the answer to this question

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John wants to invite around 78,000 college students to a tournament. Which of the following sets of college student populations

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3 years ago

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Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

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3 years ago

EXPERTS/ACE/GENIUSES/TRUSTED HELPERS HELPP ME

Mekhanik [1.2K]

B will be your best answer

The amount of points increase ~20 points each hour

just look at the point placements, and the amount each point is worth

also note that the bottom is by half hours, not hours

hope this helps

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