Question:
On a coordinate grid, point A is located in the first quadrant. Point B is located at (negative 1 over 2, 2).
Point C is a reflection of point B across the y-axis. Which graph shows these three points?
Answer:
What are you telling me? I would help, but can you type in answer choices if there is. That would be very helpful. I don't understand what is " A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.
A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the x-axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis.
A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.
A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the right of the y-axis and 4 grid lines below the x-axis."
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
![6 + 12 - 5 \times 2 + 2(8 \div 4 - 2)](https://tex.z-dn.net/?f=6%20%20%2B%2012%20-%205%20%5Ctimes%202%20%2B%202%288%20%5Cdiv%204%20-%202%29)
![6 + 12 - 10 + 2(2 - 2)](https://tex.z-dn.net/?f=6%20%2B%2012%20-%2010%20%2B%202%282%20-%202%29)
![6 + 12 - 10 + 2 \times 0](https://tex.z-dn.net/?f=6%20%2B%2012%20-%2010%20%2B%202%20%5Ctimes%200)
![6 + 12 - 10 + 0](https://tex.z-dn.net/?f=6%20%2B%2012%20-%2010%20%2B%200)
![= 8](https://tex.z-dn.net/?f=%20%3D%208)
Answer:
10) C or D
11) C
12) B
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Attached file
For this case we have the following polynomial:
x2 + px-35 = 0
We can factor the polynomial.
Rewriting we have:
(x-7) * (x + a) = 0
The value of a is given by:
-7 * a = -35
a = 35/7
a = 5
Substituting we have:
(x-7) * (x + 5) = 0
Therefore, the value of p is:
p = -7 + 5
p = -2
Answer:
the other root is:
x = -5
The value of the coefficient is:
p = -2