0.5^6 = 0.0156
Assuming an unbiased coin.
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:
For the given expression, x = 12.
Step-by-step explanation:
Here, in the given expression:
6 over x equals 4 over 8.
Now, 6 over x = 
and 4 over 8 = 
So, here 
⇒ x = 12
Hence, for the given expression, x = 12.
Answer:
<u>The correct answer is B. 1/729</u>
Step-by-step explanation:
1. Probability of any of the nine words would be randomly cited.
Using the Laplace Rule, we calculate that probability is 1/9
2. Now let's calculate the probability of any two - word phrase in specific order from those nine in the dictionary. We should remember that the probability of occurrence of two or more statistically independent events is equal to the product of their individual probabilities. So,
1/9 * 1/9 = 1/81
3. Using the same Multiplication Rule, we can calculate the probability of a random generation of the phrase "three blind mice", in that specific order. Because there are other phrases that could be generated with those three words, but in different order. The question was specific about the order.
1/9 * 1/9 * 1/9 = 1/729
<u>The probability of randomly generating the phrase "three blind mice" is 1/729 or 0.137%</u>
Answer:
4 1/3
Step-by-step explanation:
Hope this helps :)