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3 years ago

(30 points!)

Biology

2 answers:

il63 [147K]3 years ago

7 0

Answer:

an amino group, carboxyl group, hydrogen atom, and a side chain bonded to the central carbon atom

Explanation:

An amino acid essentially comprises amino group (-NH₂), carboxyl group (-COOH), hydrogen atom (-H), and a side chain (represented by R) which are attached to a central carbon atom. The central carbon atom to which all of them are attached is known as alpha carbon (α carbon). The bonds that -NH₂ and -COOH make with α carbon are known as phi (Ф) and psi (Ψ) bonds respectively.

The structure of a typical amino acid is depicted as under:

H₂N - C - COOH

The position of -NH₂ and -COOH decide whether it is a L amino acid or R amino acid.

prisoha [69]3 years ago

4 0

Answer: C. An amino group, carboxyl group and a side chain bonded to the central carbon atom.

Explanation: The amino acid structure consists of amino group, a carboxyl group (Acid group) and a side chain. These three groups are bonded to a central carbon atom.

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Which life process in the body sustains all others?

Ludmilka [50]

The life process that sustains all others is- Metabolism . Metabolism is the set of all chemical processes that take place in human body. These processes could be biological, metabolic and psychological etc. The metabolism is essential for the cells to function and overall functionality of the body like movement, digestion, excretion, reproduction and growth etc.

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3 years ago

In garden peas, tall plants (T) are dominant to short plants (t), and round pods (R) are dominant to constricted pods (r). A tru

Nataliya [291]

Answer:

Based on the given information, the study of different varieties of the garden pea was done, that is, tall plants with round pods having homozygous genotype TTRR, and the short plants with constricted pods having homozygous genotype ttrr. Post crossing the mentioned varieties of garden pea, the F1 generation comprises tall plants with round pods having the genotype TtRr. While when the crossing of F1 generation plants was done, the plants obtained in the F2 generation demonstrated the phenotype, that is, tall plants with round pods, which is 75 in number and short plants with constricted pods, which is 24 in number.

This shows that the genes would have been the linked genes, as they would have been situated very close together on the homologous chromosomes, and because of this linkage, the expression of the genes would have taken together.

In case, if there was no linkage, then the genes would have assorted independently, and the offspring produced in the F2 generation would have shown the phenotypic ratio with the features of tall plants with round pods (9), short plants with round pods (3), tall plants with constricted pods (3), and short plants with constricted pods (1).

Though the above-mentioned situation did not occur and the plants obtained in the F2 generation demonstrated the phenotype, that is, tall plants with round pods, which is 75 in number and short plants with constricted pods, which is 24 in number. This further puts more emphasis on the fact that the genes for both the phenotypes were linked due to which expression of only the mentioned two varieties took place and the other two failed to do so.

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3 years ago

What are three examples of ways in which biology can help inform everday decisions

Ilya [14]

Answer:

I not speak English

Explanation:

I speak Spanish

<3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3=================

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2 years ago

Draw a DNA molecule that has five randomly spaced restriction sites for a spedific palindrome. How many fragments would be produ

Bond [772]

Answer:

Figures attatched

Explanation:

1. Restriction enzymes cut the DNA in specific places of a specific sequence. Each restriction enzyme has different sequences of recognition.

2. Palindromic sequences are sequences that can be read the same in both senses (3' and 5'), for that reason restriction enzymes can cut both DNA strands

Now, for the first image: if a molecule has 5 restriction sites that are known for a single restriction enzyme, the enzyme will cut the DNA 5 times. If you see the image, the number of fragments is the number of restriction sites +1. In this case, it is 5+1=6 DNA fragments.

In the case of two different palindromic sequences, two different restriction enzymes recognize different sequence. If just one enzyme is present, the only cutting site will be the one that has the palindromic sequence recognizable. So, the number of fragments will be 1+1=2 DNA fragments (figure 2)

7 0

3 years ago

How many words are you responsible for this week?

arsen [322]

Answer:

how are we supposed to know how many we read today?

Explanation:

because not many people count how many words they have each week.

6 0

2 years ago