A line has the equation 3x–4y–12=0.
Is the point (2, −1) on the graph?
2 answers:
Answer:
The point (2, -1 ) is not on the graph of the line.
Step-by-step explanation:
3x–4y–12=0
3*2 - 4*(-1) - 12= 0
6 + 4 - 12 =0
10 - 12 = 0
- 2 = 0 , false, so the point (2, -1 ) is not on the graph of the line.
Answer:
It is not on the graph
Step-by-step explanation:
3x–4y–12=0
3*2 - 4*(-1) - 12= 0
6 + 4 - 12 =0
10 - 12 = 0
- 2 = 0 , false, so the point (2, -1 ) is not on the graph of the line.
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