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stiks02 [169]
3 years ago
15

Solve the problem pls and thx X + 2y > 6

Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

Solve for X=     X>6−2y

Solve for Y=     y>3−X/2

Step-by-step explanation:

musickatia [10]3 years ago
7 0

Answer:

y > 3 - x/2

slope: -1/2

y- intercept: (0,3)

Step-by-step explanation:

Solve for y:

- subtract x from both sides of inequality

2y > 6 - x

- divide each term in 2y > 6 - x by 2

2y/2>6/2+-x/2

- cancel the common factor of 2

2y/2>6/2+-x/2

- divide y by 1

y>6/2+-x/2

Simplify each term:

- divide 6 by 2

y> 3 - x/2

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Is <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B100%7D%20" id="TexFormula1" title=" \sqrt{100} " alt=" \sqrt{100} " align=
Rainbow [258]

sqrt (100) is a rational number

10*10 = 100   (-10)*(-10) =100

sqrt(100)

=-10, 10

these are rational numbers


7 0
4 years ago
In 2016, there were a total of 41 national battlefields and national memorials. The number of national memorials is three less t
goldfiish [28.3K]

Answer: 11, 30

Step-by-step explanation:

Given

There were a total of 41 national battlefields and national memorials

Suppose there are x national battlefields

So, national memorials are 3x-3

The sum of the two must be 41

\Rightarrow x+3x-3=41\\\Rightarrow 4x=44\\\Rightarrow x=11

So, there are 11 national battlefields and 3\times 11-3=30 national memorials.

3 0
3 years ago
If 70% is £14 what is the full price
Veseljchak [2.6K]
70℅ = 14
100 = X

70X = 1400

X = 1400/70

X = 20

20 Euros is the full price
6 0
3 years ago
PLEASE HELP I HAVE NO IDEA WHAT IM DOING!!!
algol13

Answer: 28.26


Step-by-step explanation:

What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²

You are given the diameter in these problems, so you need radius.

For the first circle (8 in one) :

8/2=4    r=4

A=3.14(4)²

A=50.24

For the second one (10 in one) :

10/2=5   r=5

A=3.14(5)²

A=78.5

To find the measure of the annulus, you subtract those numbers, getting 28.26


8 0
4 years ago
Factor completely 2x^3-6x^2+5x-15
Olenka [21]
2x^3-6x^2+5x-15 

2x^2(x-3)+5(x-3) 

(x-3)(2x^2+5)
4 0
3 years ago
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