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Fudgin [204]
3 years ago
9

Simplify the expression using the distributive property. –4(–3x + 11) 1. Distribute the –4 through the parentheses: -4(–3x) + (-

4)(11) 2. Find each product: x -44
Mathematics
2 answers:
diamong [38]3 years ago
8 0
Let’s start with -4(-3x + 11) so, -4•-3x is 12x,because multiplying 2 negatives creates a positive. As for -4•11, it is -44. So, it should be 12x + -44. I hope this helps!
zheka24 [161]3 years ago
6 0

Answer:

12x

Step-by-step explanation:

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(7+p)/4

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The parent graph is F(x) = x³

k - shifts the parent graph up k-units (or down if it is negative).  This is also called a vertical shift.

h - shifts the parent graph to the right h-units (or left if it is negative).  This is also called a horizontal shift.

a - stretches the parent graph vertically by a factor of "a"

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6 0
2 years ago
Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}})
\\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------

\bf \begin{cases}
h=4\\
k=1\\
p=4
\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)
\\\\\\
\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
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