1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vika [28.1K]
3 years ago
13

Anyone can help me with problem 3?

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0

Answer: 1 and 3

It's because they both divide down lower than 1

Whitepunk [10]3 years ago
3 0
Anwser is 1 and 3 because I took the test
You might be interested in
Solve for x: a(x+b)-c=d
tankabanditka [31]
D=ab-c    Theres your answer 
      a-1<span />
7 0
3 years ago
Which equation is equivalent to log Subscript 3 Baseline (x + 5) = 2?
adell [148]

Answer:

The correct option is right-bracket squared 3 squared =x+5

Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Option c: x+5=3^{2}

This is possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option c is equivalent to \log _{3}(x+5)=2

Option b: x+5=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Thus, the correct option is c: x+5=3^{2}

Hence, the equation x+5=3^{2} is equivalent to \log _{3}(x+5)=2

8 0
3 years ago
In fig if x+y=w+z then prove that AOB is a line.​
frez [133]

Answer:

As Given, x+y=w+z

To Prove: AOB is a line or x+y=180

∘

(linear pair.)

According to the question,

x+y+w+z=360

∘

∣ Angles around a point.

(x+y)+(w+z)=360

∘

(x+y)+(x+y)=360

∘

∣ Given x+y=w+z

2(x+y)=360

∘

(x+y)=180

∘

Hence, x+y makes a linear pair.

Therefore, AOB is a straight line

4 0
3 years ago
in a bag of marbles 1/2 of the marbles have a star on them if 8 marbles have a Star how many total marbles are in the bag​
Step2247 [10]

Answer:

Step-by-step explanation:

8x1/2

8/1 x 1/2

8/2

4

The answer is 4

8 0
3 years ago
Read 2 more answers
A phone sells for $137.99. It is now on sale for 1/10 off the original price. Tom has a coupon for an extra 5% off the sale pric
vlabodo [156]

Answer: Tom will pay $20.01 lesser than the original price.

Step-by-step explanation:

The original price of the phone is $137.99. It is now on sale for 1/10 off the original price. This means that the discount on the original price is 1/10 × 137.99 = 13.799. The new price will be the original price - the discount.

The new price is 137.99 - 13.799 = $124.191

Tom has a coupon for an extra 5% off the sale price. It means that Tom would pay 5% off $124.191. The amount that Tom would pay will be

124.191 - (5/100 × 124.191) = 124.191 - 6.20955 = $117.98

The difference between the original price and the price that Tom will pay is

137.99 - 117.98 = $20.01

7 0
2 years ago
Other questions:
  • Which equation solves the real world problem below?
    12·1 answer
  • Find the value of x in each case. Give reasons to justify your solutions!
    13·2 answers
  • In the diagram below AE = 6, EB = 3, and DE = 2. Find CE
    5·1 answer
  • Solve the following linear inequality: <br><br>3(x + 4) ≥ 5x – 123
    13·2 answers
  • Which of the following ratios are proportional?<br>9/12<br>12/15<br>16/20<br>20/24<br>24/35​
    9·1 answer
  • -2.5 + (-3.5)<br> Which number line shows the sum?
    9·2 answers
  • Use the diagrams below to find the lengths of the missing sides. Figures in each diagram are similar.
    6·2 answers
  • A.) 15.7in<br> B.) 31.4in<br> C.) 40in<br> D.) 62.8in
    13·2 answers
  • A side of the triangle below has been extended to form an exterior angle of 165º. Find
    7·1 answer
  • PLS HELP DUE TODAY 11:59
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!