Your answer should be 486 inches, you do 9x9 to find the area of one of the faces, and because there is 6 faces, you multiply that answer (81) to get 486
Answer:
The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches
Step-by-step explanation:
We have that:

Let the dimension of the paper be x and y;
Such that:


So:

Substitute 128 for Area

Make x the subject

When 1 inch margin is at top and bottom
The length becomes:


When 2 inch margin is at both sides
The width becomes:


The New Area (A) is then calculated as:

Substitute
for x

Open Brackets

Collect Like Terms



To calculate the smallest possible value of y, we have to apply calculus.
Different A with respect to y

Set

This gives:

Collect Like Terms

Multiply through by 


Divide through by 2

Take square roots of both sides



Recall that:



Recall that the new dimensions are:


So:




To double-check;
Differentiate A'




The above value is:

This means that the calculated values are at minimum.
<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>
Answer:
i think the endocytosis
Step-by-step explanation:
Answer:
D=(-3,3)
E=(5,0)
F=(2,-2)
Step-by-step explanation:
The coordinates are stated as =(x,y)
Answer:
Option C, Y and Z appear to be parallel lines
Hope this helps!