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3 years ago

12

Can someone pls help me with 15 and 16

1 answer:

iragen [17]3 years ago

7 0

Let say c represents for collar
Let e represents for embellishment

5c+2c <= to 1000.

I can’t help you with number 16. Sorry

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Students in a class were asked to name their favorite sport they like to watch on television. How many more time students want t

levacccp [35]

First, we need to add up all the percentages to make sure we have 100%.

25.5% + 0.03% = 25.53%

This means that 74.47% of the students chose something other than basketball or soccer.

The amount of students you stated there were was 2553.

25.5% of 2553 is 651 students and

0.03% is 8 students.

Now, we divide 651 by 8 to determine the amount of times over basketball was chosen.

651 ÷ 8 = 81

Basketball was chosen 81 times over again compared to soccer.

To find how much more times basketball was chosen, subtract 8 from 651

651 - 8 = 643

Basketball was chosen 643 times more than soccer.

8 0

4 years ago

Read 2 more answers

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

3 years ago

What line is perpendicular to the line 6x+y=-4

Arte-miy333 [17]

Answer:

DONT KNOW TO BE HONEST SEVRS ARE SWAMPED

Step-by-step explanation:

8 0

3 years ago

A pelican starts at 60 feet above sea level. It descends 60 feet to catch a fish. How do I explain this?

scoray [572]

Answer:

The answer is 0

Step-by-step explanation:

Because its original height was 60 feet above sea level but it descends to 60 feet to capture fish so 60 - 60 = 0

6 0

3 years ago

Read 2 more answers

Help ASAP!!!!!! 20 points!!

nekit [7.7K]

Answer:

Hey there!

$\frac{3+2-4^2(7)-5+2}{16-6(6)^2}$

$\frac{3+2-16(7)-5+2}{16-6(36)}$

$\frac{3+2-112-5+2}{16-216}$

$\frac{-110}{-200}$

$\frac{11}{20}$

Let me know if this helps :)

7 0

3 years ago