Answer:
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Step-by-step explanation:
d²y/dx² = (-2y² − x²) / (4y³)
Take the derivative (use quotient rule and chain rule):
d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²
d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)
d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)
d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)
d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)
Substitute:
d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)
d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Answer:
Rs 38,640
Step-by-step explanation:
<u>Pay attention:</u>
The principle (p) : Rs 42,000
Rate of interest (r) : 8%
Time (n) : 1 years
Exact Amount (a) : P(1-R/100)^n
Value:
A = 42,000(1 - 8/100)^1
A = 42,000(1 - 2/25)
A = (42,000 * 23)/25
A = 1,680 * 23
A = Rs 38,640
Answer:
if i am right it yes yes no
Step-by-step explanation:
A proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin (0,0).
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