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netineya [11]
3 years ago
9

Ashton used 12.6 gallons of gasoline to drive his car on a weekend trip. he averaged 21.5 miles per gallon. about how many miles

did he travel?
Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer: 270.9 miles.

Step-by-step explanation:

The formula  we use here is :

\text{Distance=Speed * Number of gallons of gasoline}

Given : Ashton used 12.6 gallons of gasoline to drive his car on a weekend trip. he averaged 21.5 miles per gallon.

Then \text{Distance traveled }=12.6\times21.5=270.9\text{ miles}

Hence, he traveled 270.9 miles.

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kirill [66]

Answer:

x = 3 and y = 2

or

(3,2)

Step-by-step explanation:

first equation (LCM = 3 x 4 x 5 = 60)

(x+2)/5 - (9-x)/3 = (y - 6)/4

12(x+2) - 20(9-x) = 15(y - 6)

12x + 24 - 180 + 20x = 15y - 90

32x - 15y = -90 - 24 + 180

32x - 15y = 66

second equation:

8(x + 2) - (2x + y) = 2(x + 13)

8x + 16 - 2x - y = 2x + 26

6x - y + 16 = 2x + 26

4x - y = 10

Now you have 2 equations:

4x - y = 10  ---> y = 4x - 10

32x - 15y = 66

Substitute   y = 4x - 10 into 32x - 15y = 66

32x - 15(4x - 10) = 66

32x - 60x + 150 = 66

-28x = -84

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    y = 4(3) - 10

    y = 12 - 10

    y = 2

Solutions: x = 3 and y = 2

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PLEASE HELP ME PLEASE!!
Harman [31]
  1. Answer:

hypotenuse (h)=?

perpendicular (p)=3

base(b)=2

using pythagoras theorem

h²=p²+b²

h²=3²+2²

h²=9+4

h²=13

h=√13

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  • base(b)=?

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b²=h²-p²

b²=12²-10²

b²=144-100

b=√44

b=2√11

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