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We can use the ideal gas law equation to find the volume of the balloon.
PV = nRT
where
P - pressure - 0.992 atm x 101 325 Pa/atm = 100 514 Pa
V - volume
n - number of moles - 8.80 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 25 °C + 273 = 298 K
Substituting these values in the equation
100 514 Pa x V = 8.80 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 217 L
volume of balloon is 217 L
The type of bonding present in water (H2O) is hydrogen bonding.
Answer:
pH = 10.11
Explanation:
Hello there!
In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:

We can therefore set up the corresponding equilibrium expression:
![Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_%7B18%7DH_%7B21%7DNO_4H%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_%7B18%7DH_%7B21%7DNO_4%5D%7D)
Which can be written in terms of the reaction extent,
:

Thus, by solving for
we obtain:

However, since negative solutions are now allowed, we infer the correct
is 0.0001285 M; thus, the pOH can be computed:

And finally the pH:

Best regards!