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3 years ago

f 37.4 grams of water decompose at 297 Kelvin and 1.30 atmospheres, how many liters of oxygen gas can be produced?

1 answer:

4 0

2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas

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How does sound travel through a solid?

Vedmedyk [2.9K]

The answer is C by vibrating the molecules in the matter

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2 years ago

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When the following equation is balanced with lowest whole-number coefficients, what is the coefficient for NO(g)? ___NH3(g) + __

inn [45]

Answer:

Coefficient in front of the $NO$ in the balanced equation - 4

Explanation:

The unbalanced reaction is shown below as:-

$NH_3+O_2\rightarrow NO+H_2O$

On the left hand side,

There are 1 nitrogen atom and 3 hydrogen atoms and 3 oxygen atoms

On the right hand side,

There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms

Thus,

Right side, $H_2O$ must be multiplied by 6 and $NO$ by 4

Left side, $O_2$ is multiplied by 5 and $NH_3$ by 4 so to balance the whole reaction.

Thus, the balanced reaction is:-

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

Coefficient in front of the $NO$ in the balanced equation - 4

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2 years ago

Homogenous vs heterogenous

Kruka [31]

well yah .... homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions.

while on the other hand ...A heterogeneous mixture consists of visibly different substances or phases. The three phases or states of matter are gas, liquid, and solid.

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7 0

2 years ago

A solution contains 0.0330 M Pb2 (aq) and 0.0330 M Sr2 (aq). If we add SO42–(aq), what will be the concentration of Pb2 (aq) whe

Fiesta28 [93]

The Ksp of PbSO₄ = 2.53 × 10⁻⁷
for srSO₄→ 3.44 × 10⁻⁷
for srSO₄
srSO₄→ Sr²⁺ + SO₄⁻
Ksp = [sr²⁺] [SO₄⁻]
3.44 ˣ 10⁻⁷ = (0.0330M) [ SO₄⁻]
[SO₄⁻] = 8.1 ˣ 10⁻⁶M
foe Pb SO₄
PbSO₄ →Pb²⁺ + SO₄⁻
Ksp = [ Pb²⁺] [ SO₄⁻]
2.53 ˣ 10⁻⁸M
= [ Pb²⁺] (8.1 ˣ10⁻⁶M)
[Pb²⁺] = 2.75 ˣ 10⁻³M

6 0

3 years ago

A student dissolves 15.g of styrene in 250.mL of a solvent with a density of 0.88g/mL. The student notices that the volume of th

matrenka [14]

Answer: The molarity and molality of styrene solution is 0.58 M and 0.66 m respectively

Explanation:

To calculate the mass of solvent, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solvent = 0.88 g/mL

Volume of solvent = 250. mL

Putting values in above equation, we get:

$0.88g/mL=\frac{\text{Mass of solvent}}{250mL}\\\\\text{Mass of solvent}=(0.88g/mL\times 250mL)=220g$

Calculating the molarity of solution:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of styrene = 15. g

Molar mass of styrene = 104.15 g/mol

Volume of solution (solvent) = 250. mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{15\times 1000}{104.15\times 250}\\\\\text{Molarity of solution}=0.576M=0.58M$

Calculating the molality of solution:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute (styrene) = 15 g

$M_{solute}$ = Molar mass of solute (styrene) = 104.15 g/mol

$W_{solvent}$ = Mass of solvent = 220 g

Putting values in above equation, we get:

$\text{Molality of styrene solution}=\frac{15\times 1000}{104.15\times 220}\\\\\text{Molality of styrene solution}=0.655m=0.66m$

Hence, the molarity and molality of styrene solution is 0.58 M and 0.66 m respectively.

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2 years ago