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anzhelika [568]
3 years ago
13

f 37.4 grams of water decompose at 297 Kelvin and 1.30 atmospheres, how many liters of oxygen gas can be produced?

Chemistry
1 answer:
Allisa [31]3 years ago
4 0
2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas
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3 0
3 years ago
Read 2 more answers
What is the mass in milligrams of 4.30 moles of sodium?use âeâ for âÃ10" and use significant figures?
Elis [28]

First, calculate the mass of sodium in g with the help of molar mass and number of moles.

Number of moles = \frac{given mass in g}{molar mass}   (1)

Molar mass of sodium =23 .0 g/mol

Substitute the given value of number of moles and molar mass of sodium in formula (1)

4.30 moles = \frac{given mass in g}{23.0 g/mol}   (1)

4.30 moles\times 23.0 g/mol = mass in g   (1)

mass of sodium in g = 98.9 g

Now, according to conversion factor, 1 g = 1000 mg

So, 98.9 g of sodium = 98.9 \times 1000  mg

= 98900 mg of sodium

Thus, mass of sodium in mg  =9.89 \times 10^{4} mg






8 0
3 years ago
What mass is in 5 moles of helium?
ArbitrLikvidat [17]

Answer:

Mass = 20 g

Explanation:

Given data:

Number of moles of He = 5 mol

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Solution:

Formula:

Number of moles = mass/ molar mass

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by putting values,

5 mol = Mass / 4 g/mol

Mass = 5 mol × 4 g/mol

Mass = 20 g

3 0
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