The much hydrogen that is produced is 0.02 mol of H₂ (answer B)
Explanation
2K +2H₂O→ 2 KOH + H₂
Use the mole ratio to determine the moles of H₂
From equation above the K :H₂ is 2:1
Therefore the moles of H₂ = 0.04 x 1/2 = 0.02 mol of H₂
Answer:
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Explanation:
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Hello!
To solve this problem we'll use the
Henderson-Hasselbach equation, but first we need the vale for the pKa of Benzoic acid, which is pKa= -log(Ka)=
4,19Now, we apply the equation as follows:
![pH=pKa + log ( \frac{[C_6H_5COONa]}{[C_6H_5COOH]} )=4,19+log( \frac{0,15M}{0,25M} )=3,97](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BC_6H_5COONa%5D%7D%7B%5BC_6H_5COOH%5D%7D%20%29%3D4%2C19%2Blog%28%20%5Cfrac%7B0%2C15M%7D%7B0%2C25M%7D%20%29%3D3%2C97%20)
So, the pH of this solution of Sodium Benzoate and Benzoic Acid is
3,97Have a nice day!
Answer:
10(HCl)
10H+10Cl
10+(35.453×10)
10+354.53
364.53
think it should be option <em><u>a</u></em>
Answer: 36 mol H2O (l)
Explanation:
Let's use stoichiometry to solve this problem.
12 mol C2H6 * (6 mol H2O / 2 mol C2H6) = 36 mol H2O
Hope this helps!