Answer:
185.5156 g
Explanation:
The reaction of copper sulfate with zinc is shown below as:
Given that :
Amount of copper sulfate = 454 g
Molar mass of copper sulfate = 160 g/mol
The formula for the calculation of moles is shown below:
Thus, moles are:
From the reaction,
1 mole of copper sulfate reacts with 1 mole of zinc
Thus,
2.8375 moles of copper sulfate reacts with 2.8375 moles of zinc
Moles of Zinc that should react = 2.8375 moles
Mass of zinc= moles×Molar mass
Molar mass of zinc = 65.38 g/mol
Mass of zinc = 2.8375 ×65.38 g = 185.5156 g
Answer:
197mL of 0,506M HCl
Explanation:
The reaction of HCl + BaCO₃ is:
BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.
The moles of BaCO₃ in 9,85 g are:
9,85 g of BaCO₃ × 
= <em>0,0499 moles of BaCO₃</em>
As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:
0,0499 moles of BaCO₃ × 
=<em> 0,0998 moles of HCl</em>
If you have a 0,506M HCl, you need to add:
0,0998 moles of HCl× 
= 0,197 L ≡ 197mL
I hope it helps!
Answer:
1 mole is equal to 1 moles Helium, or 4.002602 grams.
Explanation:
Answer:
Reaction products are shown below
Explanation:
- In cannizaro reaction, benzaldehyde produces benzoic acid and benzyl alcohol through disproportion.
- Here, a hydroxyl group first gives a nucleophilc addition at carbonyl center of benzaldehyde.
- Then a hydride transfer takes place to another molecule of benzaldehyde
- Thus, benzoic acid and benzyl alcohol are produced.
- Full reaction mechanism has been shown below
