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svetlana [45]
2 years ago
8

Ricky types at a rate of 68 words per minute. The equation w = 68m can be used to find w, the number of words he has typed after

m minutes. How many words are in Ricky’s essay if he typed for 35 minutes without stopping? *
Mathematics
1 answer:
algol [13]2 years ago
3 0

Answer:

2380

Step-by-step explanation:

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PLEASE HELP FAST triangle abc is translated 4 units down and 6 units right, resulting in triangle A’B’C’
Lina20 [59]

Answer:

D. (6,-1)

Step-by-step explanation:

Translating is just sliding slide the point B down 4 units from where it is and then move over 6 units to the right.

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Answer:

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Step-by-step explanation:

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Write in slope-intercept form an equation of a line that passes through the point (8, 2) that is perpendicular to the graph of t
Citrus2011 [14]

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y= -1/4 x + 4

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3 years ago
Helppppp on alllll plz
igomit [66]

a. $150

b. 150+20x\geq630

20x\geq480

x\geq24

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20x\geq600

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d. 150+20x\leq950

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3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
2 years ago
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