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andrew-mc [135]
3 years ago
9

A water trough is 7 m long and has a cross-section in the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 70 c

m wide at the top, and has height 40 cm. If the trough is being filled with water at the rate of 0.2 m3/min how fast is the water level rising when the water is 20 cm deep

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Step-by-step explanation:

Below is an attachment containing the solution.

valentina_108 [34]3 years ago
3 0

Answer:

The degree of fastness by which the water is rising is 210 seconds

Step-by-step explanation:

The volume of the trough when the water depth is 20 cm is first calculated

Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5

Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough

Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³

The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds

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The acceleration of the object will be 10 m/s²

Step-by-step explanation:

Direct variation is a relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other

  • If y varies directly with x, then y ∝ x
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For a moving object, the force acting on the object varies directly with the object's acceleration.

Assume that the force is F and the acceleration is a

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- Substitute these values in the equation above to find k

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∴ 50 = 5 a

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You can learn more about variation in brainly.com/question/10708697

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The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of
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Step-by-step explanation:

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As given in the figure radius and height of the cone are 9 and 12 respectively

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Substituting the values  

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Step-by-step explanation:

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