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ankoles [38]
3 years ago
8

A box contains 14 large marbles and 11 small marbles. Each marble is either green or white. 7 of the large marbles are green, an

d 6 of the small marbles are white. If a marble is randomly selected from the box, what is the probability that it is large or white?
Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

21/22

Step-by-step explanation:

Well, 14+11 is 25. 7/14 are green, 6/11 are white. Ok, so 7/14 large marbles are green, and 5/11 small marbles are white. So now we add.

7/14+5/11

1/2+5/11

11/22+10/22

21/22

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Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

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Brrunno [24]

Answer:

circle= 5, triangle= 3

Step-by-step explanation:

Please see attached picture for full solution.

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kakasveta [241]
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Step-by-step explanation:

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