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Paha777 [63]
2 years ago
8

Which graph represents this system? answers below A.B.C or D first one is the system

Mathematics
1 answer:
hodyreva [135]2 years ago
4 0

Answer:

A

Step-by-step explanation:

Both functions are the same Just find the value of y and you will get the same equation

Only A is correct

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Helllpp!!! Fact check my awnsers please!!!​
Mrrafil [7]

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you're all good !!

Step-by-step explanation:

6 0
2 years ago
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A jogger ran 5 2/3
Savatey [412]

5 2/3 - 1 1/4

5-2 =3

2/3 - 1/4 = 8/12 - 3/12 = 5/12

 answer is 3 5/12

6 0
3 years ago
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Warm-Up
Sveta_85 [38]

Answer:

Graph # 3

Step-by-step explanation:

-2x + 5y > 15               Let x  = 0  solve for y

 -2(0) + 5y = 15             change the > to an =

     5y = 15

      y =3     Point (0, 5) is on the graph

 Graph # 3 is correct because the y-intercept  is 5  

    x          y

    0          3                    -2(0) + 5y = 15;     5y = 15

    5          5                  -2(5) + 5y = 15;    -10 + 5y = 15;  5y = 25; y = 5

    10         7                   -2(10) + 5y = 15; -20 + 5y = 15; 5y = 35; y = 7

   The graph > the line is dotted and you will shade above the line

4 0
2 years ago
Find two unit vectors orthogonal to both 8, 5, 1 and −1, 1, 0 .
Elina [12.6K]
In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:

‹1, -1, 1› × ‹0, 1, 1›

You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.

So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...

In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0

That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:

a - b + c = 0
b + c = 0

This is two equations, three unknowns, so you can solve it with one free parameter:

b = -c
a = c - b = -2c

The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›

The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:

|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6

Then we divide that vector by its magnitude to yield one solution:

‹ -2/√6 , -1/√6 , 1/√6 ›

And take the negative for the other:

‹ 2/√6 , 1/√6 , -1/√6 ›
7 0
3 years ago
The gender of people attending a football game. a. Qualitative/nominal b.qualitative/ordinal c. Quantitative/continuous d. Quant
shtirl [24]
Answer: <span>Qualitative/nominal 

Gender is expressed as qualitative and nominal. Qualitative because it doesn't have a number, so it's not quantitative. It also nominal because gender is considered as having the same level. Another example of nominal is blood group or religion.
If it has an order of level(example: severity mild to severe), it will be ordinal.</span>
3 0
3 years ago
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