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2 years ago

6

How can i select PDF while asking questions here !!

1 answer:

saul85 [17]2 years ago

6 0

(not sure if you needed help with inserting an actual pdf or a picture) so you go to input your question like you did, but before you submit, click on the question bar where you were typing. Then it will show you your question and other little things to the left hand corner on the bottom. Click on the paper clip and then you can insert a picture. (if you already knew that and just wanted to insert an actual pdf file I don't think that you can do that but you can take a screenshot of it and then just insert that

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How to do this problem

Mumz [18]

Answer:

y = 3/2x -14

Step-by-step explanation:

do the inverse of -2/3 what is 3/2

and now sole the equation of y+8 = 3/2(x-4)

distribute 3/2 ---> y+8 = 3/2x - 8

subtract 8 from both sided getting you y=3/2x-14

7 0

2 years ago

RideAnS [48]

Answer:

$74315.50

850* 87.43 = 74315.5

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2 years ago

Guys i got an easy question for u...How is 3.098 written in words?(Easy)

IRISSAK [1]

3 and 98 thousandths

4 0

3 years ago

Read 2 more answers

The sum of three times a number and six is twelve.

Kaylis [27]

For this case we must raise the equation according to the given statement.

Let the variable "x" be the unknown number.

So, three times the number is: $3x$

If to that term is added "6" we have:

$3x+6$

The sum of both terms is "12", then:

$3x+6 = 12$

Thus, the equation is: $3x+6 = 12$

Answer:

$3x+6 = 12$

8 0

3 years ago

GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$AD = \sqrt{(-2 -6)^2 + (3 -8)^2}$

$AD = \sqrt{89}$

$CD = \sqrt{(10 -6)^2 + (2 -8)^2}$

$CD = \sqrt{52}$

$AB = \sqrt{(-2 -4)^2 + (3 +6)^2}$

$AB = \sqrt{117}$

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0

1 year ago