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3241004551 [841]
3 years ago
6

Determine if the given set is a subspace of set of prime numbers P 2. Justify your answer. The set of all polynomials of the for

m p​(t)equalsat squared​, where a is in set of real numbers R. Choose the correct answer below. A. The set is a subspace of set of prime numbers P 2. The set contains the zero vector of set of prime numbers P 2​, the set is closed under vector​ addition, and the set is closed under multiplication on the left by mtimes2 matrices where m is any positive integer. B. The set is a subspace of set of prime numbers P 2. The set contains the zero vector of set of prime numbers P 2​, the set is closed under vector​ addition, and the set is closed under multiplication by scalars. C. The set is not a subspace of set of prime numbers P 2. The set is not closed under multiplication by scalars when the scalar is not an integer. D. The set is not a subspace of set of prime numbers P 2. The set does not contain the zero vector of set of prime numbers P 2.

Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

All polynomials of the p=at² where a is in R is a subspace Pn for an appropriate value of n do not fulfill the condition and hence do not form the subspace

Step-by-step explanation:

Check attachment

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Please explain how to solve this step by step.
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Answer:

  (a^8)/(b^9)

Step-by-step explanation:

Two rules of exponents come into play.

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

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Applying the first rule, we have ...

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Answer:

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Step-by-step explanation:

<u><em> Options are: </em></u>

  • <em>2 feet </em>
  • <em>3 feet </em>
  • <em>9 feet </em>
  • <em>15 feet </em>
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<em>-------------------------------------</em>

Use the triangle inequality theorem: sum of any two side must be greater than the third side by length

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