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3 years ago

Complete the table. Multiply by 6.

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

0 * 6 = 0
5 * 6 = 30
6 * 6 = 36
6 * 8 = 48
30 * 6 = 180
50 * 6 = 300
43 * 6 = 258
120 * 6 = 720
6 * 100 = 600

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FASTEST GETS BRAINLIEST!

densk [106]

Not really well frased question. im guessing you mean the hypotonouse is 61 and the height is 11. you can use the pythagorean theorem by doing a squared plus b squared equals c squared. you know 2 variables, a and c. so you can do 11 squared plus b squared equals 61 squared. so 121 plus b squared equals 3721. then 3721-121 is 3600. the square root of 3600 is 60, giving 60 as the answer.

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3 years ago

REASONING A rectangular box for a new product is designed in such a way that

dsp73

Answer:

(2x+3) y (3x+5)

Step-by-step explanation:

For this exercise we have that the volume is

V = 6x ^ 3 + 31X ^ 2 + 53x + 30

H = X + 2

The formula for the Volume its

V = H * L * W

for find L and W (width and length) we divide V / H = L * W

So,

$\frac{V}{H} =\frac{6X^{3}+31X^{2}+53X+30 }{X+2}=(2x + 3) * (3x + 5)\\$

this division is in the attachment

so, L * W = (2x + 3) * (3x + 5)

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3 years ago

Start at 200. create a pattern that multiplies each number by 2. stop when you have 5 numbers

s2008m [1.1K]

Answer:

200 → 400 → 800 → 1600 → 3200

Step-by-step explanation:

starting at 200 and multiplying by 2 until you have 5 numbers.

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2 years ago

3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters

Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values. a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___ ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_4_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with 3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_4_ _3_ ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_4_ _3_ _2_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

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3 years ago

If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}$

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3 years ago