Question

Help please I need a decent grade

Answer 1

Answer:

h(n) = - 5.3$(-11)^{n-1}$

Step-by-step explanation:

This is a geometric sequence with n th term

h(n) = h(1) $(r)^{n-1}$

where h(1) is the first term and r the common ratio

Here h(1) = - 5.3 and r = - 11, thus

h(n) = - 5.3 $(-11)^{n-1}$ ← explicit formula

Answer 2

Answer:

h(n) = (-5.3)* (-11)^-n

Step-by-step explanation:

formula h(n) =  h(n -1 ) * (-11)

with h(1) = -5.3

Explicit formula can be found...

h(n - 1) = h(n -2) * (-11)

so if we had  h(n - A)  for A is an integer

then:   h(n - A) =  h(n) *(-11)^A

if  h (n + 1) = h(n+1 - 1) * (-11) = h(n)*(-11)

let  n > 0

so   h(1 - (-N) = h(1) *(-11)^(-N)

h(N) = (-5.3)* (-11)^-N

or   h(n) = (-5.3)* (-11)^-n