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shutvik [7]
3 years ago
8

Find an expression that is equivalent to 1 - 1/3 + 1/5 . Use denominator of 15 . plz help

Mathematics
1 answer:
love history [14]3 years ago
3 0
1 - 5/15 + 3/15
Just use common denominators!
Hope that helped. :)
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A line passes through the point (2,3) and has a slope of -2. Which is the equation of the line in point-slope form?
almond37 [142]

Answer:

7-2x=y

Step-by-step explanation:

When a point passes through a line it satisfies its equation

(X-x0 )m= y-y0

Slope = m = -2

(X-2 )(-2)=y-3

4-2x=y-3

7-2x=y

7 0
3 years ago
Solutions for 2x^2+18x=20, worth a TON, please only 100% answers ! Thank u !
victus00 [196]

Answer:

The solution of the given quadratic equation is 1 and (-10).

Step-by-step explanation:

2x^2+18x=20

x^2+9x=\frac{20}{2}

x^2+9x-10=0

ax^2+bx+c=0

Solving equation by quadratic formula:

Here , a = 1,b = 9, c = (-10)

D=b^2-4ac=(9)^2-4(1)(-10)=121

x=\frac{-b+{\sqrt{D}}}{2a}=\frac{(-9)+\sqrt{121}}{2(1)}=1

x=\frac{-b-{\sqrt{D}}}{2a}=\frac{(-9)-\sqrt{121}}{2(1)}=(-10)

The solution of the given quadratic equation is 1 and (-10).

5 0
3 years ago
If SV⊥RT, m∠RSU = (17x – 3)°, and m∠UST = (6x – 1)°, find TSV
goblinko [34]

Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

<h3>How to Apply the Linear Pair Theorem?</h3>

Given the following angles in the image above:

Measure angle RSU = (17x - 3)°,

Measure angle UST = (6x – 1)°

To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:

m∠RSU + m∠UST = 180 degrees (linear pair]

Substitute the values

17x - 3 + 6x - 1 = 180

Solve for x

23x - 4 = 180

23x = 180 + 4

23x = 184

x = 8

m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]

m∠TSV = 180 - 2(6x - 1)

Plug in the value of x

m∠TSV = 180 - 2(6(8) - 1)

m∠TSV = 86°

Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

Learn more about the linear pair theorem on:

brainly.com/question/5598970

#SPJ1

6 0
1 year ago
2 right triangles have identical angle measures but different side lengths. The first triangle has side lengths of 6, 10, 8 and
QveST [7]

Answer:

dilation is the answer

6 0
3 years ago
Please help with p and q<br> maths geometry
baherus [9]

Step-by-step explanation:

p)

in a very similar way, as the sum of all 4 angles in a triangle is always 180°, so is the sum of all angles in a quadrilateral (a polygon with 4 sides) 360°.

just look at rectangles at special representatives of such quadrilaterals.

now that we know this, we can simply say, the sum of all angles in our shape must be 360° :

(8x + 2) + (4x + 2) + (x - 2) + (5x -2) =

= 18x = 360

x = 20

A = 8×20 + 2 = 162°

B = 4×20 + 2 = 82°

C = 5×20 - 2 = 98°

D = 20 - 2 = 18°

a trapezium has the following properties (in the UK):

like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°.

a trapezium has two parallel sides and two non-parallel sides.

the diagonals of a regular trapezium bisect each other.

in the USA for example the request for 2 parallel sides does not exist.

we have proven the point with the angle sum.

the other 2 are given by the diagram.

so, yes, it is a trapezium.

q)

the sum of all interior angles of a polygon is

(n - 2) × 180°

n being the number of d sides.

we have here a regular pentagon (5 equal sides).

the size of the angle at any vertex is then

(5 - 2) × 180 / 5 = 3 × 180 / 5 = 3×36 = 108°.

so, theta = 108°.

alpha + beta = 108°

ABE is an isoceles triangle.

so, beta = angle 1

beta + angle 1 + theta = 180

2×beta + 108 = 180

2×beta = 72

beta = 36°

therefore,

alpha = 108 - beta = 108 - 36 = 72°

4 0
1 year ago
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