Answer:
123 domestic stamps
89 foreign stamps
Step-by-step explanation:
Answer:
j² - 5j²k - 2
Step-by-step explanation:
3j² - j²k - 6 - 4j²k - 2j² + 4
To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.
We have three groups of like terms:
The j-squares (j²), the j-squared k (j²k) and the constants (no variable).
Remember to include the negatives!
The j-squares are: 3j² ; -2j²
The j-squares k are: - j²k ; - 4j²k
The constants are: - 6 ; 4
Simplify:
3j² - j²k - 6 - 4j²k - 2j² + 4
Rearrange the polynomial by like terms
= (- j²k - 4j²k) + (3j² - 2j²) + (- 6 + 4)
Add or subtract the like terms
= (-5j²k) + (j²) + (-2)
Remove brackets and rearrange so the negative is not first
= j² + - 5j²k + - 2
Simplify where two signs are together. Adding a negative is subtraction.
= j² - 5j²k - 2 Simplified
Answer:
y=14/5, x=29/5
Step-by-step explanation:
Answer:
Step-by-step explanation:
So, we know that the center of the circle is at (-6, -7/6).
To find the equation of our circle that is tangent to the x-axis, we just need to find the vertical distance from our center to the x-axis.
Our center is at (-6, -7/6). The vertical distance from this to the x-axis directly above will be (-6, 0).
So, find our distance by subtracting our x-values:
Subtract:
So, our distance, which is also our radius, will be 7/6.
Now, we can use the standard form for a circle, which is:
Where (h, k) is the center and r is the radius.
Substitute -6 for h, -7/6 for k, and 7/6 for r. This yields:
We can confirm by graphing (using a calculator):
