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choli [55]
3 years ago
8

Find the Slope and the y- intercept for 5x+5y=-40

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

y-intercept= (0,-8)

slope= -1

Step-by-step explanation:

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What is the approximate value of the function at x = -8<br> A) 2<br> B) 1<br> C) 1.8<br> D) 1.5
SVETLANKA909090 [29]

Answer:

f(-8) = 1.8

Step-by-step explanation:

See the graph of a given function which is attached to the question given.

The graph of y = f(x) is plotted in the graph and we have to find the value of y at x = - 8 i.e. f(-8).

It is clear from the graph that the value of y corresponding to the value of x = -8 is slightly lower than 2.

Therefore, we can approximate the value of f(-8) as 1.8. (Answer)

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Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
PtichkaEL [24]
Okay to find the perpendicular bisector of a segment you first need to find the slope of the reference segment.

m=(y2-y1)/(x2-x1) in this case:

m=(-5-1)/(2-4)

m=-6/-2

m=3

Now for the the bisector line to be perpendicular its slope must be the negative reciprocal of the reference segment, mathematically:

m1*m2=-1  in this case:

3m=-1

m=-1/3

So now we know that the slope is -1/3 we need to find the midpoint of the line segment that we are bisecting.  The midpoint is simply the average of the coordinates of the endpoints, mathematically:

mp=((x1+x2)/2, (y1+y2)/2), in this case:

mp=((4+2)/2, (1-5)/2)

mp=(6/2, -4/2)

mp=(3,-2)

So our bisector must pass through the midpoint, or (3,-2) and have a slope of -1/3 so we can say:

y=mx+b, where m=slope and b=y-intercept, and given what we know:

-2=(-1/3)3+b

-2=-3/3+b

-2=-1+b

-1=b

So now we have the complete equation of the perpendicular bisector...

y=-x/3-1 or more neatly in my opinion :P

y=(-x-3)/3
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Get y by it self and then graph it. Should be y=5x+4
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Find the value of x.<br> A<br> B<br> X<br> 6<br> 3<br> 2<br> D<br> x = [?]<br> C
GrogVix [38]

Answer:

Step-by-step explanation:

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What does the blank equal??
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Answer:

To a power, elevated to something

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