Answer:
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To answer this question, remember the formula ∆X = Vot + 1/2 at^2
To solve, all you have to do is plug in the numbers.
∆X = height of the ledge (the unknown)
t = time (8 seconds)
a = acceleration (9.8 m/s^2)
Vo = initial velocity
∆X = 0(8) + 1/2(9.8m/s^2)(8s)^2
∆X = 0 + 313.6 m
∆X = 313.6 meters
Your answer would be B, 313.6 meters
As long as the magnet is moving ...
... there is voltage between the ends of the wire in the coil, and
... if there is any kind of conductor between the ends, then there is current flowing through the coil.
I included things
Hope this helps!
Answer:
The water will flow at a speed of 3,884 m/s
Explanation:
Torricelli's equation
v =
*v = liquid velocity at the exit of the hole
g = gravity acceleration
h = distance from the surface of the liquid to the center of the hole.
v = = 3,884 m/s