The car's mass is 1600 kg.
Its weight is (mass) x (gravity).
On Earth, that's (1600 kg) x (9.8 m/s²) = 15,680 Newtons.
At the moment, that's the only force acting on the car, directed downward and provided by gravity.
If you want to lift the car, then the net force has to be directed upward, and must either exactly cancel or exceed the force of gravity.
So the minimum force required to lift the car is <em>15,680 Newtons</em>, directed vertically upward.
Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
I think you're saying that once you start pushing on the cars, you want to be able to stop each one in the same time.
This is sneaky. At first, I thought it must be both 'c' and 'd'. But it's not
kinetic energy, for reasons I'm not ambitious enough to go into.
(And besides, there's no great honor awarded around here for explaining
why any given choice is NOT the answer.)
The answer is momentum.
Momentum is (mass x speed). Change in momentum is (force x time).
No matter the weight (mass) or speed of the car, the one with the greater
momentum is always the one that will require the greater (force x time)
to stop it. If the time is the same for any car, then more momentum
will always require more force.
Answer rain gauge measures rain shadow units millimetres
