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3 years ago

Summarize what you learned this week about the electromagnetic spectrum

Physics

2 answers:

svetoff [14.1K]3 years ago

8 0

Answer:

I only really know the "How do we use these EM waves in our lives?" part srry

Explanation:

EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.

emmainna [20.7K]3 years ago

5 0

Electromagnetic spectrum consists of
Radio waves
Microwaves
Infrared
Visible light
Ultraviolet
X-ray
Gamma ray

We use these everyday in our life however they also have dangers.

Radio waves - their long wavelength allows them to help with communication
Danger - exposure to a lot of radio waves can cause cancer or leukaemia

Microwaves - used for heating up food and transferring heat to the food.
Dangers - exposure can cause cancers and other diseases.

Infrared - can be used for remote controls and security cameras.
Danger - can cause damage to the cornea in your eye

Visible light - used for photography and optical fibres.
Danger - intense sources can cause permanent or temporary damage to the eyesight.

Ultraviolet - can be used to sterilise food and sterilise surgical equipment.
Danger - can cause skin damage and may lead to a cancer.

X-rays - used to see the internal structure of tissues and bones.
Dangers - can lead to mutations and May damage the cells

Gamma- can be used to sterilise food and surgical equipment and kill microorganisms and other bacteria.
Dangers - May reach your cells and cause cancer and cell mutations which could result in mutations.

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This shot is made while your body is not directly facing the basket<br><br><br> (P.E. Sub)

Phoenix [80]

The correct answer is hook shot

8 0

2 years ago

How will the motion of a falling whirligig compare to that of a falling paper ball?

kicyunya [14]

The motion of a falling whirligig is different to that of a falling paper ball due to spinning.

<h3>Type of motion performed by whirligig and falling paper ball </h3>

The motion of a falling whirligig is different from the motion of a falling paper ball because the paper ball falls on the ground without spinning while on the other hand, the whirligig falls on the ground along with spinning.

The falling whirligig performs two motion i.e. one is falling on the ground and the other is spinning during motion whereas paper ball performs one motion i.e. motion in the air towards the ground so we can conclude that the motion of a falling whirligig is different than of a falling paper ball.

Learn more about motion here: brainly.com/question/453639

4 0

2 years ago

A bus contains a 1440 kg flywheel (a disk that has a 0.63 m radius) and has a total mass of 10200 kg. Calculate the angular velo

CaHeK987 [17]

Answer: $\omega =93.51 rad/s$

Explanation:

Given

mass of Flywheel $m_1=1440 kg$

mass of bus $m_b=10200 kg$

radius of Flywheel $r=0.63 m$

final speed of bus $v=21 m/s$

Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let $\omega$ be the angular velocity of Flywheel

$0.9\cdot \frac{I\omega ^2}{2}=\frac{m_bv^2}{2}$

$I=moment\ of\ Inertia =mr^2=1440\cdot 0.63^2=571.536 kg-m^2$

$0.9\cdot \frac{571.536\cdot \omega ^2}{2}=\frac{10200\cdot 21^2}{2}$

$\omega ^2=21^2\times \frac{10200}{0.9\times 571.536}$

$\omega =21\times 4.45=93.51 rad/s$

8 0

3 years ago

Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope

Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

= -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

= 26,754 (0.816)

= 21,835 J