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11Alexandr11 [23.1K]
3 years ago
7

Summarize what you learned this week about the electromagnetic spectrum

Physics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

I only really know the "How do we use these EM waves in our lives?" part srry

Explanation:

EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.

emmainna [20.7K]3 years ago
5 0
Electromagnetic spectrum consists of
Radio waves
Microwaves
Infrared
Visible light
Ultraviolet
X-ray
Gamma ray

We use these everyday in our life however they also have dangers.

Radio waves - their long wavelength allows them to help with communication
Danger - exposure to a lot of radio waves can cause cancer or leukaemia

Microwaves - used for heating up food and transferring heat to the food.
Dangers - exposure can cause cancers and other diseases.

Infrared - can be used for remote controls and security cameras.
Danger - can cause damage to the cornea in your eye

Visible light - used for photography and optical fibres.
Danger - intense sources can cause permanent or temporary damage to the eyesight.

Ultraviolet - can be used to sterilise food and sterilise surgical equipment.
Danger - can cause skin damage and may lead to a cancer.

X-rays - used to see the internal structure of tissues and bones.
Dangers - can lead to mutations and May damage the cells

Gamma- can be used to sterilise food and surgical equipment and kill microorganisms and other bacteria.
Dangers - May reach your cells and cause cancer and cell mutations which could result in mutations.
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Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con
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Answer:

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given,

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assume the distance be r from q₁  where the electric field is zero.

distance of point from q₂  be equal to 1.8 -r

now,

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\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}

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1.8 = 6 r

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<h3>b) zero when one charge is negative.</h3>

let us assume  q₁  be negative so, distance from  q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

   E₁ = E₂

\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}

(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}

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1.8 =4 r

r = 0.45 m

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