I'm assuming it was to keep the data consistent? The further you are from a heat source the less heat will get to you as the temperature tries to reach equilibrium and the waves start to spread out, so you should keep everything the same distance to get consistent results. I don't have any information so this is just my assumption
Answer:
The tension in the middle string is 3.3 N
Explanation:
Two boxes move with same acceleration
The tension in the middle string is T
Lets start with the forces acting in the 2nd box
→ The tension T in the string in the direction of motion
Due to Newtons's Law
→ ∑ Force in direction of motion = mass × acceleration
→ T = M a
→ M = 1 kg
Substitute the value of M is the equation
→ T = a ⇒ (1)
The force acting on the 1st box
→ The force F in the direction of motion, and T in the string in opposite
direction of motion
→ F - T = 2M a
→ F = 10 N , M = 1 kg
Substitute These values in the equation
→ 10 - T = 2(1) a
→ 10 - T = 2 a ⇒ (2)
Substitute equation (1) in (2)
→ 10 - T = 2 T
Add T to both sides
→ 10 = 3 T
Divide both sides by 3
→ T = 3.3 N
<em>The tension in the middle string is 3.3 N</em>
The net force on the box parallel to the plane is
∑ F[para] = mg sin(24°) = ma
where mg is the weight of the box, so mg sin(24°) is the magnitude of the component of its weight acting parallel to the surface, and a is the box's acceleration.
Solve for a :
g sin(24°) = a ≈ 3.99 m/s²
The box starts at rest, so after 7.0 s it attains a speed of
(3.99 m/s²) (7.0 s) ≈ 28 m/s
The answer is dispersion!
Explanation:
Boyles law is the pressure of a fixed mass of gas which is inversely proportional to its volume provided that the temperature is kept constant.
