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2 years ago

5

Sound waves cannot travel in

1 answer:

julsineya [31]2 years ago

5 0

Answer:

The answer is D. A Vacumn

Explanation:

Sound cannot travel through a vacuum. A vacuum is an area without any air, like space. So sound cannot travel through space because there is no matter for the vibrations to work in.

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Give a specific example of a vector quantity. why this type of quantity would be used to describe this event ?

Anarel [89]

example force. because you can say" I applied 3 newtons downward to the floor".

force has magnitude and direcion

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3 years ago

A carrot hangs from the ceiling by a rope,

valentina_108 [34]

Answer: Diagram B

Explanation:

A free body diagram shows the forces acting on an object in a certain scenario.

In this scenario there are two forces acting on the carrot: the Tension force (Ft) from the rope that the carrot is hanging from and Gravitational force(Fg) which is pulling the carrot to the Earth.

The diagram depicting this is diagram B.

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2 years ago

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A brick is thrown from a wall that is 19.2 m above the ground and hits the ground 5.00 s later. What was the initial velocity of

Brums [2.3K]

Answer:

0

Explanation:

Given the following :

Height of wall = 19.2 m

Time taken to hit the ground = 5 seconds

Acceleration due to gravity (g) = 9.8m/s ( downward motion)

The initial velocity of the object refers to the Velocity of the object at time t = 0

Initial Velocity = g × time

Initial Velocity = 9.8 × 0 = 0

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3 years ago

Which of these is most likely to lead directly to a black market?

Sloan [31]

The answer is C.rationing.

<span>♡♡Hope I helped!!! :)♡♡
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3 years ago

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You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the

Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed , $\omega=\frac{v}{r}$

Using the formula

$\omega=\frac{0.49}{0.27}=1.8 rad/s$

$\omega=\frac{2\pi}{T}$

$T=\frac{2\pi}{\omega}$

Time period, $T=\frac{2\pi}{1.8}=3.49 s$

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed, $V_{max}=0.49 m/s$

d.Maximum acceleration= $a=r\omega^2=0.27(1.8)^2=0.87 m/s^2$

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3 years ago

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